问题描述
我正在尝试使用以下代码创建信用卡类型的文本,但无法执行此操作,有什么办法吗?
I am trying to create credit card type text with following code, but not able to do that, is there any way to do?
func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
let formatter = NSNumberFormatter()
formatter.groupingSize = 4
formatter.groupingSeparator = "-"
formatter.usesGroupingSeparator = true
print("txtCardNumber \(txtCardNumber.text)")
}
推荐答案
以下逻辑实现了带空格的16位简单信用卡格式.
Below logic implements simple 16 digits credit card formatting with spaces.
代码已针对Swift 4/5进行了调整
第1步:为信用卡文本字段创建操作
Step 1: Create an action for for credit card textfield
self.txtFieldCreditCardNumber.addTarget(self, action: #selector(didChangeText(textField:)), for: .editingChanged)
第2步:从文本字段的选择器方法中调用一个将进行格式化的方法
Step 2: Call a method from this selector method of textfield that will do the formatting
@objc func didChangeText(textField:UITextField) {
textField.text = self.modifyCreditCardString(creditCardString: textField.text!)
}
第3步:实现方法"modifyCreditCardString"
Step 3: Implement the method "modifyCreditCardString"
func modifyCreditCardString(creditCardString : String) -> String {
let trimmedString = creditCardString.components(separatedBy: .whitespaces).joined()
let arrOfCharacters = Array(trimmedString)
var modifiedCreditCardString = ""
if(arrOfCharacters.count > 0) {
for i in 0...arrOfCharacters.count-1 {
modifiedCreditCardString.append(arrOfCharacters[i])
if((i+1) % 4 == 0 && i+1 != arrOfCharacters.count){
modifiedCreditCardString.append(" ")
}
}
}
return modifiedCreditCardString
}
第4步:实现UITextField的委托,这将卡号限制为16个字符. 19 = 16 + 3(每4位数字后1个空格)
Step 4: Implement the delegate of UITextField, which will restrict the card numbers to 16 characters. 19 = 16 + 3 (1 spaces after each 4 digits)
func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
let newLength = (textField.text ?? "").count + string.count - range.length
if(textField == txtFieldCreditCardNumber) {
return newLength <= 19
}
return true
}
希望这会有所帮助.谢谢
Hope this will help. Thanks
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