MongoDB $lookup 嵌套文档

问题描述

我是 mongo 的新手，正在努力解决以下问题.我有 2 个集合，结构如下.对于我的生活，我无法弄清楚如何对学校收藏进行 $lookup .阅读其他帖子，我肯定使用 ObjectId 作为参考以及外国字段.

I'm new to mongo and struggling mightily with the following. I have 2 collections structured as below. For the life of me, I can't figure out how to do a $lookup on the school collection. Reading other posts, I'm definitely using ObjectId for the reference as well as the foreign field.

以下是我的结构:

校友:

{
    "_id": "john",
    "items": [
        {
            "name": "John",
            "items": [
                {
                    "school": ObjectId("56de35ab520fc05b2fa3d5e4"),
                    "grad": true
                },
                {
                    "school": ObjectId("56de35ab520fc05b2fa00000"),
                    "grad": false
                }
            ]
        },
        {
            "name": "Johnny"
            // notice no nested items, this doc should still be included in result
        },
        {
            "name": "Jon",
            "items": [
                {
                    "school": ObjectId("56de35ab520fc05b2fa11111"),
                    "grad": false
                }
            ]
        }
     ]
}

学校

{
    _id: ObjectId("56de35ab520fc05b2fa3d5e4"),
    name: "Some University",
    street: "ABC Boulevard"
}

我想得到什么:

{
    "_id": "john",
    "items": [
        {
            "name": "John",
            "items": [
                {
                    "school": ObjectId("56de35ab520fc05b2fa3d5e4"),
                    "grad": true,
                    "schoolInfo":     {
                        _id: ObjectId("56de35ab520fc05b2fa3d5e4"),
                        name: "Some University",
                        street: "ABC Boulevard"
                    }
                },
                {
                    "school": ObjectId("56de35ab520fc05b2fa00000"),
                    "grad": true,
                    "schoolInfo":     {
                        _id: ObjectId("56de35ab520fc05b2fa00000"),
                        name: "Another University",
                        street: "123 Boulevard"
                    }
                }
            ]
        },
        {
            name: "Johnny"
        },
        {
            "name": "Jon",
            "items": [
                {
                    "school": ObjectId("56de35ab520fc05b2fa11111"),
                    "grad": true,
                    "schoolInfo":     {
                        _id: ObjectId("56de35ab520fc05b2fa11111"),
                        name: "Some University",
                        street: "ABC Boulevard"
                    }
                }
            ]
         }
     ]
}

我尝试过的查询无济于事:

The query I've tried to no avail:

db.alumni.aggregate([
      {$match: {_id: 'john'}},
      {$lookup: {
                from: 'schools',
                localField: 'items.items.school',
                foreignField: '_id',
                as: 'schoolInfo'}}
 ])

任何帮助将不胜感激！

推荐答案

在这种情况下，需要在聚合框架中很好地使用 $unwind 和 $project

in this case there is required a nice play with $unwind and $project in aggregation framework

请看下面:

db.alumni.aggregate([
    {$match: {_id: 'john'}},
    {$unwind:"$items"},
    {$unwind:"$items.items"},
    {$lookup: {
        from: 'schools',
        localField: 'items.items.school',
        foreignField: '_id',
        as: 'schoolInfo'}},
    {$unwind:"$schoolInfo"},
    {$project:{
        "_id":1,
        "items":[{
            "name":"$items.name",
            "items":[{
            "school":"$schoolInfo._id"    ,
            "grad":"$items.items.grad"    ,
            "schoolInfo":"$schoolInfo"
            }]
        }]
    }}
]).pretty()

看看它是如何工作的 - 尝试从查询中删除聚合阶段并检查文档结构.

to see how it works - try removing aggregation stages from query and check document structure.

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