本文介绍了TypeError:b.lat不是函数-热图图层的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我一直在努力弄清楚为什么我的加热层遇到上述问题.我在坐下时看到的答案解决了不正确的LatLng设置,但是我的标记器的LatLng数组工作得很好.

I'm stuck trying to figure out why I'm getting the above issue for my heat-layer. The answers I've seen on while seatching address improper LatLng setup, however my marker's LatLng array work just fine.

即使api说它是可选的,我也尝试过添加权重.

I've tried adding weights as well even though the api say it's optional.

var map;

function initMap(resultSet) {
  map = new google.maps.Map(document.getElementById('maps'), {
    center: {
        lat: 40.8173,
        lng: -96.7005
    },
    zoom: 16,
    mapTypeId: 'satellite'
  });`

  var labels = [];
  var locations = [];

  for (var i = 0; i < resultSet.length; i++) {
    labels.push(resultSet[i][0]);
    locations.push({
        lat: parseFloat(resultSet[i][3]),
        lng: parseFloat(resultSet[i][4])
    });
    if (data[0] == '1') {
        var marker = new google.maps.Marker({
            position: locations[i],
            map: map,
            title: labels[i]
        });
        marker.setMap(map);
    }
  }

  if (data[0] == '2') {
    var heatmap = new google.maps.visualization.HeatmapLayer({
        data: locations,
    });
    heatmap.setMap(map);
  }
}

推荐答案

HeatmapLayer 是您不能使用 google.maps.LatLngLiteral 的位置,必须 google.maps.LatLng 对象.(您得到的错误是因为匿名对象 LatLngLiteral 没有 .lat()方法,它具有 .lat 属性)

The HeatmapLayer is one of the remaining places you can't use a google.maps.LatLngLiteral for a position, it must be a google.maps.LatLng object.(the error you get is because the anonymous object LatLngLiteral doesn't have a .lat() method, it has a .lat property).

更改:

for (var i = 0; i < resultSet.length; i++) {
    labels.push(resultSet[i][0]);
    locations.push({
        lat: parseFloat(resultSet[i][3]),
        lng: parseFloat(resultSet[i][4])
    });
    if (data[0] == '1') {
        var marker = new google.maps.Marker({
            position: locations[i],
            map: map,
            title: labels[i]
        });
        marker.setMap(map);
    }
}

收件人:

for (var i = 0; i < resultSet.length; i++) {
    labels.push(resultSet[i][0]);
    locations.push(new google.maps.LatLng(
        parseFloat(resultSet[i][3]),
        parseFloat(resultSet[i][4])
    ));
    if (data[0] == '1') {
        var marker = new google.maps.Marker({
            position: locations[i],
            map: map,
            title: labels[i]
        });
        marker.setMap(map);
    }
}

这篇关于TypeError:b.lat不是函数-热图图层的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

09-16 09:09