问题描述
我使用 CLLocationDistance 来获得两点之间的距离，但是在传递我当前位置时出现错误。
I'm using CLLocationDistance to get the distance between two points, but I'm getting an error when passing my current location in it.
CLLocation *current = [[CLLocation alloc] initWithLatitude:startLocation.coordinate.latitude longitude:startLocation.coordinate.longitude];
CLLocation *itemLoc = [[CLLocation alloc] initWithLatitude:[[[getName objectAtIndex:indexPath.row] objectForKey:@"lat"] doubleValue] longitude:[[[getName objectAtIndex:indexPath.row] objectForKey:@"lon"] doubleValue]];
//Here the current location gives me an error "Initializing cllocation with an expression incompatible format"
CLLocationDistance *itemDist = [itemLoc distanceFromLocation:current];
NSLog(@"Distance: %@", itemDist);
推荐答案
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The error you're getting is actually:
它的意思是你正在初始化 itemDist CLLocationDistance （通知无星号）
What it's saying is you're initializing itemDist (which you've declared as a CLLocationDistance *) to something that is returning a CLLocationDistance (notice no asterisk).
CLLocationDistance 不是对象。
它只是一个原始类型（特别是 double - 请参阅）。
因此， code>作为指针添加到 CLLocationDistance ，只需将其声明为 CLLocationDistance （no asterisk）：
So instead of declaring itemDist as a pointer to a CLLocationDistance, just declare it as a CLLocationDistance (no asterisk):
CLLocationDistance itemDist = [itemLoc distanceFromLocation:current];
您还需要更新 NSLog 以期望 double 而不是对象，否则会在运行时崩溃：
You'll also need to update the NSLog to expect a double instead of an object otherwise it will crash at run-time:
NSLog(@"Distance: %f", itemDist);
这篇关于使用CLLocation计算两个坐标之间的距离的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！