SQL查询以匹配多个字符串之一

问题描述

我在表中有以下数据：

  + --------------- ------- + ------------------------------------------ ---------------- + -------------- + 
 | subscription_fields_id |名称| field_type | 
 + ---------------------- + ---------------------- ------------------------------------ + ------------- -+ 
 | 143 |白沙瓦/伊斯兰堡/拉合尔/特警/马尔丹/卡拉奇|工作地点
 | 146 |卡拉奇|工作地点
 | 147 |拉合尔和卡拉奇|工作地点
 | 149 |卡拉奇，米尔布尔·卡斯，苏库尔，拉耶，吉尔吉特，查萨达|工作地点
 | 152 |伊斯兰堡或拉合尔|工作地点
 | 155 |伊斯兰堡|工作地点
 | 157 |信德省和卡拉奇7区|工作地点
 + ---------------------- + ---------------------- ------------------------------------ + ------------- -+ 
  

我的查询是：

  select *从用户区域
中选择，其中的名称如'％Khairpur，Islamabad，Karachi％'； 
  

结果：

  + ---------------------- + --------------------- -------------------------- + -------------- + 
 | subscription_fields_id |名称| field_type | 
 + ---------------------- + ---------------------- ------------------------- + -------------- + 
 | 143 |白沙瓦/伊斯兰堡/拉合尔/特警/马尔丹/卡拉奇|工作地点
 | 152 |伊斯兰堡或拉合尔|工作地点
 | 155 |伊斯兰堡|工作地点
 + ---------------------- + ---------------------- ------------------------- + -------------- + 
  

它应该返回名称包括伊斯兰堡，海毛尔或卡拉奇但未包含在内的所有行。

解决方案

要获得适当的解决方案，请，或者除此以外，考虑。 p>

要快速解决当前的问题，请使用或三个简单的表达式：

 选择* 
 FROM Subscriberfields 
 WHERE名称〜’（（Khairpur |伊斯兰堡| Karachi）’）； 
  

或：

  ... 
 WHERE（名称为'％Khairpur％'或
名称为'％Islamabad％'或
名称为'％Karachi％'）
  

或使用〜* 或 ILIKE 用于不区分大小写的匹配。

由于另一个答案建议：从不使用 SIMILAR到：

I have following data in table:

+----------------------+----------------------------------------------------------+--------------+
| subscriber_fields_id | name                                                     | field_type   |
+----------------------+----------------------------------------------------------+--------------+
|                  143 | Peshawar/Islamabad/Lahore/Swat/Mardan/Karachi            | Job Location |
|                  146 | Karachi                                                  | Job Location |
|                  147 | Lahore and Karachi                                       | Job Location |
|                  149 | Karachi, Mirpur Khas, Sukkur, Layyah, Gilgit, Charsaddah | Job Location |
|                  152 | Islamabad or Lahore                                      | Job Location |
|                  155 | Islamabad                                                | Job Location |
|                  157 | 7 Districts of Sindh and Karachi                         | Job Location |
+----------------------+----------------------------------------------------------+--------------+

My query is:

select * from subscriberfields
where  name like '%Khairpur,Islamabad,Karachi%';

Result:

+----------------------+-----------------------------------------------+--------------+
| subscriber_fields_id | name                                          | field_type   |
+----------------------+-----------------------------------------------+--------------+
|                  143 | Peshawar/Islamabad/Lahore/Swat/Mardan/Karachi | Job Location |
|                  152 | Islamabad or Lahore                           | Job Location |
|                  155 | Islamabad                                     | Job Location |
+----------------------+-----------------------------------------------+--------------+

It should return all rows where the name includes Islamabad, Khairpur or Karachi but it is not.

解决方案

For a proper solution, either normalize your database design or, barring that, consider full text search.

For a quick solution to the problem at hand, use a regular expression match (~) or three simple LIKE expressions:

SELECT *
FROM   subscriberfields
WHERE  name ~ '(Khairpur|Islamabad|Karachi)';

Or:

...
WHERE (name LIKE '%Khairpur%' OR
       name LIKE '%Islamabad%' OR
       name LIKE '%Karachi%')

Or use ~* or ILIKE for case-insensitive matching.

Since another answer suggested it: never use SIMILAR TO:

• Using SIMILAR TO for a regex?
• Pattern matching with LIKE, SIMILAR TO or regular expressions in PostgreSQL

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