本文介绍了从地理编码器结果中获取城市?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
从地理编码器结果中获取不同数组内容时遇到问题.
Having problems getting the different arrays content from geocoder results.
item.formatted_address 有效但 item.address_components.locality 无效?
item.formatted_address works but not item.address_components.locality?
geocoder.geocode( {'address': request.term }, function(results, status) {
response($.map(results, function(item) {
alert(item.formatted_address+" "+item.address_components.locality)
}
});
//返回的数组为;
"results" : [
{
"address_components" : [
{
"long_name" : "London",
"short_name" : "London",
"types" : [ "locality", "political" ]
} ],
"formatted_address" : "Westminster, London, UK" // rest of array...
感谢任何帮助!
直流
推荐答案
最终使用:
var arrAddress = item.address_components;
var itemRoute='';
var itemLocality='';
var itemCountry='';
var itemPc='';
var itemSnumber='';
// iterate through address_component array
$.each(arrAddress, function (i, address_component) {
console.log('address_component:'+i);
if (address_component.types[0] == "route"){
console.log(i+": route:"+address_component.long_name);
itemRoute = address_component.long_name;
}
if (address_component.types[0] == "locality"){
console.log("town:"+address_component.long_name);
itemLocality = address_component.long_name;
}
if (address_component.types[0] == "country"){
console.log("country:"+address_component.long_name);
itemCountry = address_component.long_name;
}
if (address_component.types[0] == "postal_code_prefix"){
console.log("pc:"+address_component.long_name);
itemPc = address_component.long_name;
}
if (address_component.types[0] == "street_number"){
console.log("street_number:"+address_component.long_name);
itemSnumber = address_component.long_name;
}
//return false; // break the loop
});
这篇关于从地理编码器结果中获取城市?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!