如何制作嵌套比例面积图（圆圈）？

问题描述

我正在寻找python中可以用来在圈子中绘制嵌套比例面积图的任何内容。最好使用matplotlib构建（或在其之上）。以下是此类绘图的示例供您参考：

I'm looking for anything in python that I can use to do a nested proportional area chart in circles. Preferably something built with (or on top of) matplotlib. Here's an example of what such plot looks like for reference:

推荐答案

一个嵌套的圆形图，其中圆形面积与数据成比例，如下所示。
它将使用排序后的列表或数据数组以及可选的相应标签作为输入，并绘制几个圆。

A nested circle diagram, where the circle area is proportional to the data could look as follows.It would take a sorted list or array of data and optionally the respective labels as input and plot a couple of circles.

import numpy as np
import matplotlib.pyplot as plt
from matplotlib.collections import PatchCollection


def nested_circles(data, labels=None, c=None, ax=None,
                   cmap=None, norm=None, textkw={}):
    ax = ax or plt.gca()
    data = np.array(data)
    R = np.sqrt(data/data.max())
    p = [plt.Circle((0,r), radius=r) for r in R[::-1]]
    arr = data[::-1] if c is None else np.array(c[::-1])
    col = PatchCollection(p, cmap=cmap, norm=norm, array=arr)

    ax.add_collection(col)
    ax.axis("off")
    ax.set_aspect("equal")
    ax.autoscale()

    if labels is not None:
        kw = dict(color="white", va="center", ha="center")
        kw.update(textkw)
        ax.text(0, R[0], labels[0], **kw)
        for i in range(1, len(R)):
            ax.text(0, R[i]+R[i-1], labels[i], **kw)
    return col

用法可能看起来像

data = [1,3,4,5,6]
labels = list("ABCDE")
nested_circles(data, labels=labels, cmap="copper", textkw=dict(fontsize=14))
plt.show()

如果您想要其他颜色编码，请使用 c 参数并提供另一个列表值，例如

If you want a different colorcoding, take the c argument and supply another list of values, e.g.

data = [1,3,4,5,6]
labels = list("ABCDE")
codes = [5,3,1,4,2]
circles = nested_circles(data, labels=labels, c=codes, cmap="plasma",
                         textkw=dict(color="black", fontsize=14))
plt.colorbar(circles, label="Codes")
plt.title("Diagram")
plt.show()

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