使用Accessors设置用户名

本文介绍了使用Accessors设置用户名的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 限时删除！！ 我有一个继承自Bass类的Character类。在运行时，我希望用户输入字符名称。我想使用SetName访问器来完成此操作。我尝试过多种方法让它发挥作用。我创造了一个新的角色英雄;并尝试传递Hero.SetName（cin，sName）; 哪个不起作用。调试器告诉我sName没有在main.cpp文件的范围内声明。我的问题是如何使用Set访问器获取用户名并保持封装的主要内容。我可以为My heros名称传递一个全局变量，但是我失去了封装的好处。我的Main.cpp文件和Charecter类发布在下面谢谢。 #include < iostream > #include < string > #include < cstdlib > #include < cmath > #include < ctime > #includeCharacterClass.h使用namespace std ; int main（） { srand（time（0））; CharecterClass Hero; cout < < 输入 您的 名称 挑战者： ; // system（cls）; Hero.SetName（cin， sName）; Hero.SetHealth（5）; Hero.SetAttack（（rand（）％ 12） + 1）; cout << Hero.GetName（） << endl; cout < < Hero.GetHealth（） << endl; cout << Hero.GetAttack（） << ; endl; return 0; } #ifndef CHARACTERCLASS_H #define CHARACTERCLASS_H #include BaseClass。 h #include< iostream> class CharacterClass： public BaseClass { public ： CharacterClass（）; virtual ~CharacterClass（）; int GetArmor（）{ return m_CharacterArmor; } int GetAttack（）{ return m_CharacterAttack; } int GetDamage（）{ return m_CharacterDamage; } void SetArmor（ int nCharacterArmor）{m_CharacterArmor = nCharacterArmor; } void SetAttack（ int nCharacterAttack）{m_CharacterAttack = nCharacterAttack; } void SetDamage（ int nCharacterDamage）{m_CharacterDamage = nCharacterDamage; } 受保护： 私人： int m_CharacterArmor; int m_CharacterAttack; int m_CharacterDamage; }; ＃endif // CHARACTERCLASS_H #ifndef BASECLASS_H #define BASECLASS_H #include< iostream> class BaseClass { public ： BaseClass（）; virtual ~BaseClass（）; std :: string GetName（）{ return m_Name; } int GetHealth（）{ return m_Health; } void SetName（std :: string sName） {m_Name = sName; } void SetHealth（ int nHealth）{m_Health = nHealth; } 受保护： 私人： std :: string m_Name; int m_Health; }; ＃endif // BASECLASS_H 解决方案 要使用我的访问器设置名称，我创建了一个带有本地字符串变量的函数，我将返回Hero.SetName（）。这对我保持我的课程封装起来很有用。 string HeroName（） { string sTemp; cout<< 输入你的名字挑战者：; cin>> STEMP; 返回sTemp; } 这是它的实施 Hero .SetName（HeroName（））; I Have a Character class that inherits from a Bass class. At run time I want the user to enter the characters name. I want to do this using the SetName Accessor. I''ve tried multiple ways to get this to work. I created a new Character Hero; and tried to pass Hero.SetName(cin, sName);Which did not work. The debugger tells me that sName is not declared in the scope of my main.cpp file. My question is is how do I go about getting a users name using the Set accessor and keeping with the pricipal of encapsulation. I can pass a global variable for My heros name but I lose the benefit of encapsulation. My Main.cpp file and Charecter class are posted below thanks.#include <iostream>#include <string>#include <cstdlib>#include <cmath>#include <ctime>#include "CharacterClass.h"using namespace std;int main(){ srand(time(0)); CharecterClass Hero; cout << "Enter your name Challenger: "; //system("cls"); Hero.SetName(cin, sName); Hero.SetHealth(5); Hero.SetAttack((rand()% 12) + 1); cout << Hero.GetName() << endl; cout << Hero.GetHealth() << endl; cout << Hero.GetAttack() << endl; return 0;}#ifndef CHARACTERCLASS_H#define CHARACTERCLASS_H#include "BaseClass.h"#include <iostream>class CharacterClass : public BaseClass{ public: CharacterClass(); virtual ~CharacterClass(); int GetArmor() { return m_CharacterArmor; } int GetAttack() { return m_CharacterAttack; } int GetDamage() { return m_CharacterDamage; } void SetArmor(int nCharacterArmor) { m_CharacterArmor = nCharacterArmor; } void SetAttack(int nCharacterAttack) { m_CharacterAttack = nCharacterAttack; } void SetDamage(int nCharacterDamage) { m_CharacterDamage = nCharacterDamage; } protected: private: int m_CharacterArmor; int m_CharacterAttack; int m_CharacterDamage;};#endif // CHARACTERCLASS_H#ifndef BASECLASS_H#define BASECLASS_H#include <iostream>class BaseClass{ public: BaseClass(); virtual ~BaseClass(); std::string GetName() { return m_Name; } int GetHealth() { return m_Health; } void SetName(std::string sName) { m_Name = sName; } void SetHealth(int nHealth) { m_Health = nHealth; } protected: private: std::string m_Name; int m_Health;};#endif // BASECLASS_H 解决方案 To set the name using my accessor I created a function with a local string variable which I return to Hero.SetName(). This worked for me keeping my class encapsulated.string HeroName(){string sTemp;cout << "Enter your name challenger:";cin >> sTemp;return sTemp;}and here is it''s implementationHero.SetName(HeroName()); 这篇关于使用Accessors设置用户名的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 1403页，肝出来的..