GNU中的递归通配符使?

启动器:我需要递归搜索flac目录，并在mp3目录中创建相应的子目录.目录和文件的名称中可以包含空格，并以UTF-8命名.我想用make来驱动它.解决方案我会尝试以下方法FLAC_FILES = $(shell find flac/ -type f -name '*.flac')MP3_FILES = $(patsubst flac/%.flac, mp3/%.mp3, $(FLAC_FILES)).PHONY: allall: $(MP3_FILES)mp3/%.mp3: flac/%.flac @mkdir -p "$(@D)" @echo convert "$<" to "$@"针对make初学者的一些快速笔记:命令前面的@阻止make在实际运行命令之前打印命令. $(@D)是目标文件名($@)的目录部分确保其中带有shell命令的行以制表符开头，而不以空格开头.即使这可以处理所有UTF-8字符和内容，它也会在文件或目录名称中的空格处失败，因为make使用空格分隔makefile中的内容，并且我不知道解决方法那.恐怕只剩下一个shell脚本了:-/It's been a while since I've used make, so bear with me...I've got a directory, flac, containing .FLAC files. I've got a corresponding directory, mp3 containing MP3 files. If a FLAC file is newer than the corresponding MP3 file (or the corresponding MP3 file doesn't exist), then I want to run a bunch of commands to convert the FLAC file to an MP3 file, and copy the tags across.The kicker: I need to search the flac directory recursively, and create corresponding subdirectories in the mp3 directory. The directories and files can have spaces in the names, and are named in UTF-8.And I want to use make to drive this. 解决方案 I would try something along these linesFLAC_FILES = $(shell find flac/ -type f -name '*.flac')MP3_FILES = $(patsubst flac/%.flac, mp3/%.mp3, $(FLAC_FILES)).PHONY: allall: $(MP3_FILES)mp3/%.mp3: flac/%.flac @mkdir -p "$(@D)" @echo convert "$<" to "$@"A couple of quick notes for make beginners:The @ in front of the commands prevents make from printing the command before actually running it.$(@D) is the directory part of the target file name ($@) Make sure that the lines with shell commands in them start with a tab, not with spaces.Even if this should handle all UTF-8 characters and stuff, it will fail at spaces in file or directory names, as make uses spaces to separate stuff in the makefiles and I am not aware of a way to work around that. So that leaves you with just a shell script, I am afraid :-/ 这篇关于GNU中的递归通配符使?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！