问题描述
我有一个文件夹，包含许多文件.有一个包含pc_0.txt，pc_1.txt，...，pc_699.txt的组.我想选择pc_200->到pc_699.txt之间的所有文件
I have a folder, contains many files.There is a group contains pc_0.txt,pc_1.txt,...,pc_699.txt.I want to select all files beetween pc_200 - > to pc_699.txt
如何?
for filename in glob.glob("pc*.txt"):
global_list.append(filename)
推荐答案
对于这种特定情况，glob已经支持您所需要的内容(请参阅 fnmatch全局通配符文档).您可以这样做:
For this specific case, glob already supports what you need (see fnmatch docs for glob wildcards). You can just do:
for filename in glob.glob("pc[23456]??.txt"):
如果您需要更具体地说明两个结尾字符是数字(某些文件中可能包含非数字字符)，则可以将?替换为[0123456789]，但是否则，我会找到分心一点.
If you need to be extra specific that the two trailing characters are numbers (some files might have non-numeric characters there), you can replace the ?s with [0123456789], but otherwise, I find the ? a little less distracting.
在更复杂的情况下，您可能被迫诉诸正则表达式，并且可以在此处执行以下操作:
In a more complicated scenario, you might be forced to resort to regular expressions, and you could do so here with:
import re
for filename in filter(re.compile(r'^pc_[2-6]\d\d\.txt$').match, os.listdir('.')):
但是考虑到通配符通配符已经足够好用了，您现在还不需要大手笔.
but given that glob-style wildcards work well enough, you don't need to break out the big guns just yet.
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