我如何获得 pandas 的年龄和日期的年龄

问题描述

这是我的数据

Customer_id    Date-of-birth
1              1992-07-02
2              1991-07-03

这是我的代码

import datetime as dt
df['now'] = dt.datetime.now()
df['age'] = df['now'].dt.date - df['Date-of-birth']

这是结果

Customer_id    Date-of-birth     age
1              1992-07-02        xxxx days
2              1991-07-03        xxxx days

我想要的结果是

Customer_id    Date-of-birth     age
1              1992-07-02        26 years 22 days
2              1991-07-03        27 years 21 days

现在让我们根据 df.dtypes ，出生日期是一个对象，因为它基于下拉菜单中的客户输入

Just let you now, by df.dtypes, Date-of-birth is an object because is based on customer input in dropdown

我该如何实现?我希望这个问题足够清楚

How can I achieve this? I hope the question is clear enough

推荐答案

将此解决方案与自定义功能一起使用，因为计算它是不容易，因为leap年:

Use this solution with custom function, because count it is not easy because leaps years:

from dateutil.relativedelta import relativedelta

def f(end):
    r = relativedelta(pd.to_datetime('now'), end)
    return '{} years {} days'.format(r.years, r.days)

df['age'] = df["Date-of-birth"].apply(f)
print (df)
   Customer_id Date-of-birth               age
0            1    1992-07-02  26 years 22 days
1            2    1991-07-03  27 years 21 days

这篇关于我如何获得 pandas 的年龄和日期的年龄的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！