如何将经纬度转换为XY坐标系(例如UTM)，然后将其映射到我的图像的像素空间

问题描述

我有一个很小的区域地图，我从Openstreet地图(PNG)和它的OSM(.osm)文件中下载了该文件，其中包含Lat，long.

I have a very small area map , which I downloaded from Openstreet map(PNG) and also its OSM(.osm) file which contains its Lat ,long.

现在，我想将Lat long转换为XY坐标系(例如UTM)，然后将其映射到大小为(600 x 800)的我的Image像素空间.我知道它是一个双向过程，就像想知道如何做到这一点.谢谢

Now I want to convert Lat ,long to an XY coordinate system (e.g. UTM) and then map this to pixel space of my Image which is of size (600 x 800 ). I know its a two way process ,like to know how to do this . Thank you

推荐答案

GPS坐标到像素

• 假设此地图未跨越本初子午线
• 假设像素0,0位于左上方，像素600,800位于右下方.

• 假设地图仅是北半球(地图的任何部分都不是南半球)

  GPS Coordinates to Pixels

  • Assuming this map does not cross prime meridian
  • Assuming pixel 0,0 is upper left, and pixel 600,800 is lower right.

  • Assuming map is Northern Hemisphere Only (no part of map is southern hemisphere)

    1. 确定800x600图像(X)中最左边的经度
    2. 确定800x600图像(Y)中最东的经度
    3. 确定经度差(Z = Y-X)
    4. 确定800x600图像(A)中的最北纬度
    5. 确定800x600图像(B)中最南端的纬度
    6. 确定经度差(C = A-B)

  给出纬度和经度，以确定他们单击了哪个像素:

  Given a Latitude and Longitude, to determine which pixel they clicked on:

  1. J =输入经度

  2. k =输入纬度

  1. J = Input Longitude

  2. K = Input Latitude

  计算X像素

  XPixel = CInt((((Y-J)/CDbl(Z))* 800)

  XPixel = CInt(((Y - J) / CDbl(Z)) * 800)

  计算Y像素

  YPixel = CInt((((A-K)/CDbl(C))* 600)

  YPixel = CInt(((A - K) / CDbl(C)) * 600)

  UTM

  这是一个制图图书馆，该数据库应有助于GPS到UTM的转换

  UTM

  Here is a cartographic library that should help with GPS to UTM conversions

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