本文介绍了用Java增加数字的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧! 问题描述 这是我的代码。由于某种原因,我的BMI计算不正确。 当我在计算器上检查输出时:(10 /((10/100)^ 2)))我得到1000,但在我的程序中我得到5.我不确定我做错了什么。这是我的代码:Here is my code. For some reason my BMI is not calculated correctly.When I check the output on a calculator for this : (10/((10/100)^2))) I get 1000, but in my program, I get 5. I'm not sure what I am doing wrong. Here is my code:import javax.swing.*;public class BMI { public static void main(String args[]) { int height; int weight; String getweight; getweight = JOptionPane.showInputDialog(null, "Please enter your weight in Kilograms"); String getheight; getheight = JOptionPane.showInputDialog(null, "Please enter your height in Centimeters"); weight = Integer.parseInt(getweight); height = Integer.parseInt(getheight); double bmi; bmi = (weight/((height/100)^2)); JOptionPane.showMessageDialog(null, "Your BMI is: " + bmi); }} 推荐答案 ^ 并不意味着提高功率。这意味着XOR。^ in java does not mean to raise to a power. It means XOR.你可以使用java的 Math.pow() You can use java's Math.pow()您可能要考虑使用 double 而不是 int -that is:And you might want to consider using double instead of int—that is:double height;double weight;请注意 199/100 评估为1 。 这篇关于用Java增加数字的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!
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