SequenceEqual特定的属性

问题描述

我想比较对象的两个列表。的对象有四个不同的性质。我只需要三个人来比较的序列（只有三个，因为一个总是有所不同）。

I would like to compare two lists of objects. The objects have four different properties. I need to compare only three of them as sequence (only three because one is always different).

一个例子是如下：

list1 = new List<myClass>() { new myClass(10, "a", 100, "unique1"),
    new myClass(10, "a", 100, "unique2") };

list2 = new List<myClass>() { new myClass(10, "a", 100, "unique3"),
    new myClass(10, "a", 100, "unique4") };

我可以比较那些列为序列而无需对第四（唯一）的财产？对于exapmle期望中的结果将是TRUE。

Can I compare those lists as sequence without the fourth (unique) property? Desired result for the exapmle would be TRUE.

任何想法如何解决这个问题？

Any ideas how to solve this?

推荐答案

您可以使用过载，使您可以在传递一个的IEqualityComparer< T> 实现，仅包括要比较的属性。

You could use the SequenceEqual overload that allows you to pass in an IEqualityComparer<T> implementation that only includes the properties that you wish to compare.

这连结网页上的例子是一个很好的一个。

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