本文介绍了file_exists()无法正常工作的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在与Codeigniter合作.我要显示图像,但如果不存在某些图像,则应显示 image-not-found-medium.jpg
这是虚拟图像.
I am working with codeigniter. I want to display images but if some image is not exist it should show image-not-found-medium.jpg
which is dummy image..
下面是我的代码
<?php
$image_path_medium = site_url('assets/images-products/medium');
$image_not_found_medium = $image_path_medium . "/" . "image-not-found-medium.jpg";
$image_name_with_path = $image_path_medium . "/" . $home_technology[$key]->product_sku . "-" . "a" . "-medium.jpg";
if (file_exists($image_name_with_path)) {
echo $image_name_with_path;
} else {
echo $image_not_found_medium;
}
?>
但它始终显示 $ image_not_found_medium
,我认为我的 if条件
存在问题.请帮忙.
but it always shows $image_not_found_medium
i think there is problem with my if condition
.Please help.
推荐答案
<?php
$image_path_medium = site_url('assets/images-products/medium');
$image_not_found_medium = $image_path_medium . "/" . "image-not-found-medium.jpg";
$image_name_with_path = $image_path_medium . "/" . $home_technology[$key]->product_sku . "-" . "a" . "-medium.jpg";//this is your image url
$image_file_path=FCPATH.'assets/images-products/medium'. $home_technology[$key]->product_sku . "-" . "a" . "-medium.jpg";//this is your file path
if (file_exists($image_file_path)) //file_exists of a url returns false.It should be real file path
{
echo $image_name_with_path;
}
else
{
echo $image_not_found_medium;
}
?>
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