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问题描述

我一直在使用sort()函数,但它混合了相对顺序.

I've been using the sort() function but it mixes up the relative order.

这是我的代码的外观.

This is how my code looks.

recipes.sort { $0.skill.value <= $1.skill.value }

Swift API 表示:

如何更改此设置,以使相对顺序保持与以前相同?

How can I change this so that the relative order stays the same as before?

推荐答案

let sortedArray = (recipes as NSArray).sortedArray(options: .stable, usingComparator: { (lhs, rhs) -> ComparisonResult in
    let lhs = (lhs as! Recipe)
    let rhs = (rhs as! Recipe)
    if lhs.skill.value == rhs.skill.value {
        return ComparisonResult.orderedSame
    } else if lhs.skill.value < rhs.skill.value {
        return ComparisonResult.orderedAscending
    } else {
        return ComparisonResult.orderedDescending
    }
})

从此处获取: https://medium.com/@cocotutch/a-swift-sorting-problem-e0ebfc4e46d4

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10-15 05:55