本文介绍了无法在 org.hibernate.mapping.Table(user_details) 及其相关的超级表和辅助表中找到具有逻辑名称的列:user_details_id的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试创建简单的单向映射.我正在使用 MappedSuperclass 和 @JoinColumn,可能有问题.看起来实体无法从超类中找到 id 字段.
I am trying to create simple unidirectional mapping. I am using MappedSuperclass and @JoinColumn and there is probably a problem. Looks like entity cannot find id field from super class.
异常:
Caused by: org.hibernate.MappingException: Unable to find column with logical name: user_details_id in org.hibernate.mapping.Table(user_details) and its related supertables and secondary tables
at org.hibernate.cfg.Ejb3JoinColumn.checkReferencedColumnsType(Ejb3JoinColumn.java:832) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
at org.hibernate.cfg.BinderHelper.createSyntheticPropertyReference(BinderHelper.java:256) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
at org.hibernate.cfg.ToOneFkSecondPass.doSecondPass(ToOneFkSecondPass.java:101) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
at org.hibernate.boot.internal.InFlightMetadataCollectorImpl.processEndOfQueue(InFlightMetadataCollectorImpl.java:1827) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
at org.hibernate.boot.internal.InFlightMetadataCollectorImpl.processFkSecondPassesInOrder(InFlightMetadataCollectorImpl.java:1771) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
at org.hibernate.boot.internal.InFlightMetadataCollectorImpl.processSecondPasses(InFlightMetadataCollectorImpl.java:1658) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
at org.hibernate.boot.model.process.spi.MetadataBuildingProcess.complete(MetadataBuildingProcess.java:287) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.metadata(EntityManagerFactoryBuilderImpl.java:904) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:935) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
超级班:
@Getter
@Setter
@MappedSuperclass
public abstract class BaseEntity {
@Id
@GeneratedValue(
strategy = GenerationType.IDENTITY
)
private Long id;
}
消息实体(加入发送方和接收方的ID)
Message entity (Joins id's of both sender and receiver)
@Getter
@Setter
@NoArgsConstructor
@AllArgsConstructor
@Builder
@Entity(name = "Message")
@Table(name = "message")
public class Message extends BaseEntity {
private String title;
private String details;
private String message_container;
private LocalDate dataOfSending;
@ManyToOne(optional = false)
@JoinColumn(name = "sender_id", referencedColumnName = "user_details_id")
private UserDetails sender;
@ManyToOne(optional = false)
@JoinColumn(name = "receiver_id", referencedColumnName = "user_details_id")
private UserDetails receiver;
}
用户详细信息(不应该知道消息)
User Details (should not know about messages)
@Getter
@Setter
@Builder
@NoArgsConstructor
@AllArgsConstructor
@Entity(name = "UserDetails")
@Table(name = "user_details")
public class UserDetails extends BaseEntity {
private String firstName;
private String lastName;
private String motherName;
private String fatherName;
private String personalIdentityNum;
private LocalDate dateOfBirth;
@OneToOne
@JoinColumn(name = "user_id")
private User user;
@OneToOne(mappedBy = "userDetails")
private Address address;
@OneToOne(mappedBy = "userDetails")
private Contact contact;
@OneToOne(mappedBy = "userDetails")
private ProfileImage profileImage;
}
有什么想法吗?提前致谢.
Any ideas? Thank you in advance.
推荐答案
你可以在 Message
类中更改此部分
Can you just change this section in Message
class
@ManyToOne(optional = false)
@JoinColumn(name = "sender_id", referencedColumnName = "user_details_id")
private UserDetails sender;
@ManyToOne(optional = false)
@JoinColumn(name = "receiver_id", referencedColumnName = "user_details_id")
private UserDetails receiver;
到
@ManyToOne
@JoinColumn(name = "sender_id")
private UserDetails sender;
@ManyToOne
@JoinColumn(name = "receiver_id")
private UserDetails receiver;
并在UserDetails
中添加这些代码
@OneToMany(mappedBy = "sender")
private List<Message> senderMessage = new ArrayList<>();
@OneToMany(mappedBy = "receiver")
private List<Message> receiverMessage = new ArrayList<>();
这篇关于无法在 org.hibernate.mapping.Table(user_details) 及其相关的超级表和辅助表中找到具有逻辑名称的列:user_details_id的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!