本文介绍了如何提取两个不同时间值之间的营业时间的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

对于评估由服务台处理的故障单,我想知道故障单有多少个工作时间。我可以轻松地减去时间并获得总小时数。但是唯一应该计数的时间是在08:30到18:00之间。

For the evaluation of tickets processed by a help desk I would like to know how many business hours an ticket is active. I can easily subtract the times and get the total amount of hours. But the only hours that should count are between 08:30 and 18:00.

例如:如果在 11/23创建票证/ 2015 10:20 并在 2015/11/24 17:20 完成,那么已经过去了31个正常小时。我只对过去的营业时间(在8:30到18:00之间)感兴趣;在这种情况下 16小时30分钟

For example: if a ticket is created at 11/23/2015 10:20 and completed on 11/24/2015 17:20, then 31 'normal' hours have passed. I'm only interested in the business hours (between 8:30 and 18:00) that have passed; in this case 16 hours and 30 minutes

推荐答案

library(lubridate)

   tickets <- data.frame(open = as.POSIXct(strptime(df$open, "%m/%d/%Y %H:%M")),
                      closed = as.POSIXct(strptime(df$closed, "%m/%d/%Y %H:%M"))


excludeDayCount <- Vectorize(function(open, close) {

   # Check if the ticket was open and closed on the same day
   if (identical(as.Date(open), as.Date(close))) return (0)

   # All the holidays to be excluded need to be put here
   holidays <- as.POSIXct(strptime(c("12/24/2015", "12/25/2015"),
                                  "%m/%d/%Y"))

   # Dates between open and close
   day_seq <- floor_date(seq(open + days(1), close, by = "days"), "day")

   # Count holidays / weekend days
   return(sum(day_seq %in% holidays | wday(day_seq) %in% c(1,7)))

})

bizHrDiff <- function(open, close) {

    # Hours from the end of one work day until the start of another
    hours_between_days <- dhours(6) + dhours(8.5)

    # Number of days to exclude
    excl_days <- excludeDayCount(open, close)
    # Number of days in include
    reg_days <- as.integer(as.Date(close) - as.Date(open)) - excl_days



    # Total duration between dates
      span <- as.duration(interval(open, close))
      # Remove the number of holidays and weekends
      span <- span - ddays(excl_days)
      # Remove out of office hours
      span <- span - (reg_days * hours_between_days)




     # Return in hours
      return(time_length(span, unit = "hour"))


}

bizHrDiff(tickets$open, tickets$closed)

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09-06 05:56