本文介绍了在UITableViewCell内部带有超链接的UILabel应该打开safari webbrowser吗?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个带有两个标签的自定义 UITableViewCell
( UILabel
)。表格单元格用于显示信息/文本。在其中一些单元格(不是全部)中,以这种方式设置文本:
I have a custom UITableViewCell
with two labels (UILabel
). The table cells are used to display information / text. Inside some of these cells (not all) there is text in this way set:
cell.myTextlabel.text = @"http://www.google.de"
现在我想要点击此文字/链接, safari webbrowser应该打开这个网页。我怎么能这样做?
Now I want if I click this text / link, a safari webbrowser should open this webpage. How can I do this?
最好的问候蒂姆。
推荐答案
将userInteractionEnabled设置为标签的YES,并为其添加手势识别器:
Set userInteractionEnabled to YES of your label and add a gesture recognizer to it:
myLabel.userInteractionEnabled = YES;
UITapGestureRecognizer *gestureRec = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(openUrl:)];
gestureRec.numberOfTouchesRequired = 1;
gestureRec.numberOfTapsRequired = 1;
[myLabel addGestureRecognizer:gestureRec];
[gestureRec release];
然后实施行动方法:
- (void)openUrl:(id)sender
{
UIGestureRecognizer *rec = (UIGestureRecognizer *)sender;
id hitLabel = [self.view hitTest:[rec locationInView:self.view] withEvent:UIEventTypeTouches];
if ([hitLabel isKindOfClass:[UILabel class]]) {
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:((UILabel *)hitLabel).text]];
}
}
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