我试图在一个名为 my_exp(x) 的函数中使用麦克劳林级数来近似 e^x，我相信到目前为止我所做的一切都是正确的，但我得到了不正确的近似值无论我尝试什么号码.
导入数学对于范围 (x) 中的 i:exp = 1 + ((x**i)/math.factorial(i))打印(exp)例如，每当我尝试 my_exp(12) 我得到 18614.926233766233 而不是 162754.79141900392帮助?
你的问题是 e^x 级数是一个无限级数，所以只对级数的前 x 项求和是没有意义的.
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def myexp(x):e=0for i in range(0,100): #Sum the first 100项e=e+(x**i)/math.factorial(i)返回 e您还可以定义结果的精度并获得更好的解决方案.
def myexp(x):e=0压力=0.0001s=1我=1当 s>pre:e=e+ss=(x**i)/math.factorial(i)我=我+1返回 eI'm trying to approximate e^x using the Maclaurin series in a function called my_exp(x), I believe everything I've done so far is right but I'm getting incorrect approximations for whatever number I try.
import math
for i in range (x):
exp = 1 + ((x**i)/math.factorial(i))
print(exp)
For example, whenever I try my_exp(12) I get 18614.926233766233 instead of 162754.79141900392Help?
Your problem is that the e^x series is an infinite series, and so it makes no sense to only sum the first x terms of the series.
def myexp(x):
e=0
for i in range(0,100): #Sum the first 100 terms of the series
e=e+(x**i)/math.factorial(i)
return e
You can also define the precision of your result and get a better solution.
def myexp(x):
e=0
pres=0.0001
s=1
i=1
while s>pres:
e=e+s
s=(x**i)/math.factorial(i)
i=i+1
return e
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