本文介绍了如何格式化星火Python的输出的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
(u'142578', (u'The-North-side-9890', (u' 12457896', 45.0)))
(u'124578', (u'The-West-side-9091', (u' 14578217', 0.0)))
这是我从加入基于IDS这就像两个RDD了(键,(value_left,value_right))使用此星火加入。
,所以我希望能有像
The-North-side-9890,12457896,45.0
The-West-side-9091,14578217,0.0
为了这个,我尝试用以下code
for this i try with the following code
from pyspark import SparkContext
sc = SparkContext("local", "info")
file1 = sc.textFile('/home/hduser/join/part-00000').map(lambda line: line.split(','))
result = file1.map(lambda x: (x[1]+', '+x[2],float(x[3][:-3]))).reduceByKey(lambda a,b:a+b)
result = result.map(lambda x:x[0]+','+str(x[1]))
result = result.map(lambda x: x.lstrip('[(').rstrip(')]')).coalesce(1).saveAsTextFile("hdfs://localhost:9000/finalop")
但给我下面的输出
but giving me the following output
(u'The-North-side-9896', (u' 12457896',0.0
(u'The-East-side-9876', (u' 47125479',0.0
所以我要清理这个,我怎么能做到这一点。
so i want to clean this how could i do that
帮助我实现这一目标。
推荐答案
从此得到:
(u'142578',(u'The北端-9890'(U'12457896',45.0)))
这样:
的 - 北 - 侧9890,12457896,45.0
您需要使用:
result = result.map(lambda (k, (s, (n1, n2))): ','.join([s, str(int(n1)), str(float(n2))]))
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