如何提取两个标记之间的子字符串?

使用 sed 可以用字符串做这样的事情:echo "$STRING" |sed -e "s|.*AAA\(.*\)ZZZ.*|\1|"这将给我 1234 结果.如何在 Python 中做同样的事情? 解决方案 使用正则表达式 - 文档以供进一步参考导入重新文本 = 'gfgfdAAA1234ZZZuijjk'm = re.search('AAA(.+?)ZZZ', 文字)如果米:找到 = m.group(1)# 找到:1234或:导入重新文本 = 'gfgfdAAA1234ZZZuijjk'尝试:found = re.search('AAA(.+?)ZZZ', text).group(1)除了属性错误:# AAA, ZZZ 在原始字符串中找不到found = '' # 应用你的错误处理# 找到:1234Let's say I have a string 'gfgfdAAA1234ZZZuijjk' and I want to extract just the '1234' part.I only know what will be the few characters directly before AAA, and after ZZZ the part I am interested in 1234.With sed it is possible to do something like this with a string:echo "$STRING" | sed -e "s|.*AAA\(.*\)ZZZ.*|\1|"And this will give me 1234 as a result.How to do the same thing in Python? 解决方案 Using regular expressions - documentation for further referenceimport retext = 'gfgfdAAA1234ZZZuijjk'm = re.search('AAA(.+?)ZZZ', text)if m: found = m.group(1)# found: 1234or:import retext = 'gfgfdAAA1234ZZZuijjk'try: found = re.search('AAA(.+?)ZZZ', text).group(1)except AttributeError: # AAA, ZZZ not found in the original string found = '' # apply your error handling# found: 1234 这篇关于如何提取两个标记之间的子字符串?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！