提供多个当SpecFlow方案陈述

本文介绍了提供多个当SpecFlow方案陈述的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

相当新的SpecFlow如此容忍我。

Fairly new to SpecFlow so bear with me.

我和一位同事努力让你可以用SpecFlow做一个基本的了解。

I was working with a colleague to get a basic understanding of what you can do with SpecFlow.

我们分别采用了经典的FizzBuzz问题，这是我们用来测试的单元测试来比较，我们会怎么做SpecFlow类似的问题。

We were using the classic FizzBuzz problem, which we have used to test unit testing to compare how we would do a similar problem in SpecFlow.

我们写我们的方案如下代码越来越需要：

we wrote our scenarios as follows growing the code as needed:

（请原谅命名只是想获得测试令状）

(please excuse naming just wanted to get the tests writ)

Scenario: 1 is 1
    Given there is a FizzBuzzFactory
    When you ask What I Am with the value of 1
    Then the answer should be 1 on the screen

Scenario: 3 is Fizz
    Given there is a FizzBuzzFactory
    When you ask What I Am with the value of 3
    Then the answer should be Fizz on the screen

Scenario: 5 is Buzz
    Given there is a FizzBuzzFactory
    When you ask What I Am with the value of 5
    Then the answer should be Buzz on the screen

Scenario: 15 is FizzBuzz
    Given there is a FizzBuzzFactory
    When you ask What I Am with the value of 15
    Then the answer should be FizzBuzz on the screen

这导致进化发展，将计算方法一些数字的总和。

This lead to an evolution to develop a method that would calculate a sum of some numbers

我们写的情况是：

Scenario: Sumof 1 + 2 + 3 is Fizz
    Given there is a FizzBuzzFactory
    When you add the sum of 1
    When you add the sum of 2
    When you add the sum of 3
    Then the answer should be Fizz on the screen

我们写了接受一个的方法。在同一时间数再总结

The method we wrote accepted one number at a time to then sum up.

理想我将提供：

Scenario: Sumof 1 + 2 + 3 in one go is Fizz
    Given there is a FizzBuzzFactory
    When you add the sum of 1,2,3
    Then the answer should be Fizz on the screen

你怎么能去有关设置语句，这样，你可以期望一个 PARAMS INT [] 的方法签名。

How can you go about setting up the statement so that you can expect a params int[] on the method signature.

推荐答案

您的问题是支持真的很好由specflow一步绑定，如果你使用了 StepArgumentTransformation 。这就是为什么我喜欢specflow。

Your problem is supported really nicely by the specflow step bindings, if you use a StepArgumentTransformation. This is why I love specflow.

[When(@"you add the sum of (.*)")]
public void WhenYouAddTheSumOf(int[] p1)
{
    ScenarioContext.Current.Pending();
}

[StepArgumentTransformation(@"(\d+(?:,\d+)*)")]
public int[] IntArray(string intCsv)
{
    return intCsv.Split(',').Select(int.Parse).ToArray();
}

这里的StepArgumentTransformation将允许你采取任何逗号分离的任何整数列表从现在开始步定义，并接受它作为一个数组参数。

The StepArgumentTransformation here will allow you to take any comma separated list of ints in any step definition from now on, and accept it as an Array parameter.

如果你想StepArgumentTransformations玩，使他们很好的和具体这是值得我们学习的几个正则表达式位。注意：我可以使用（\d +（？：，\d +）*）。而不是 * 中在当绑定了。

It's worth learning a few regex bits if you want to play with StepArgumentTransformations, to make them nice and specific. Note I could have used (\d+(?:,\d+)*) instead of .* in the When binding too.

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