我怎样才能申请simpleExpandableListAdapter或类似的东西的ListView在ListFragment

问题描述

我正与ListFragment，并希望做出一个艰难的名单，其中有子列表，不知道我能做到这一点（（有些code：

I am working with ListFragment and want to make a difficult list, which has sublists and don't know how I can do it((Some code:

public class CarsOfBrandFragment extends ListFragment {
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        ...
        String[] s = {"colorName"};
        int[] k = {R.id.groupname};
        String[] s1 = new String[]{"shadeName", "rgb"};
        int[] k1 = new int[]{R.id.childname, R.id.rgb};
        SimpleExpandableListAdapter expListAdapter = new SimpleExpandableListAdapter(getActivity(), createGroupList(),
            R.layout.grouprow, s, k, createChildList(), R.layout.childrow, s1, k1);
        setListAdapter(expListAdapter);
    }

setListAdapter（android.widget.ListAdapter）在android.support.v4.app.ListFragment不能适用于（android.widget.SimpleExpandableListAdapter）

setListAdapter(android.widget.ListAdapter) in android.support.v4.app.ListFragment cannot be applied to (android.widget.SimpleExpandableListAdapter)

推荐答案

好吧，我决定这个被明确说明 ExapndableListView 的 - 是的，我改变了对扩展平常的ListView，并使用 SimpleCursorTreeAdapter 而不是 SimpleExpandableListAdapter

Ok I decided this by explicit indicating of ExapndableListView - yes I changed usual ListView on Expandable, and using SimpleCursorTreeAdapter instead of SimpleExpandableListAdapter

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