问题描述
我在我的应用中使用多个屏幕。我编写了从第一个屏幕移动到第二个屏幕，第二个屏幕移动到第三个屏幕的代码，依此类推到第五个屏幕。
I'm using multiple screens in my app. I wrote code for the moving from the first screen to the second screen, the second screen to the third screen, and so on up to the fifth screen.
现在我想跳到第五个屏幕的第一个屏幕，但我想这样做而不创建第一个屏幕的另一个实例，因为这会导致内存问题。
Now I want to jump to the first screen from the fifth screen, but I want to do this without creating another instance of the first screen, as that would cause memory problems.
请建议在这种情况下该怎么办？
Please suggest what to do in this case?
推荐答案
[self.navigationController popToRootViewControllerAnimated：YES];
[self.navigationController popToRootViewControllerAnimated:YES];
[self.navigationController popToViewController：[self.navigationController.viewControllers objectAtIndex：0] animated：YES];
[self.navigationController popToViewController:[self.navigationController.viewControllers objectAtIndex:0] animated:YES];
您可以使用第二行代码然后验证视图控制器的索引。
You can use second line code then verify the index of view controller.
并且您有内存问题所以请验证任何对象是否释放。
and you have memory problem so please verify the any object release or not.
这篇关于在通过五个屏幕转换后，回到我的iPhone应用程序的第一个屏幕的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！