本文介绍了我怎样才能点击一个按钮启动微调控制的ItemSelected事件?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我在我的应用程序setOnItemSelectedListener一个微调框控件,当我选择微调的项目,该事件onItemSelected将陆续推出。
现在,我希望能点击一个按钮来启动onItemSelected事件,我该怎么办?谢谢!
spinnerFolder.setOnItemSelectedListener(新OnItemSelectedListener(){
@覆盖
公共无效onItemSelected(适配器视图<>为arg0,ARG1观,诠释ARG2,长ARG3){
//完成业务逻辑
}
@覆盖
公共无效onNothingSelected(适配器视图<>为arg0){
}
});
解决方案
只需拨打您的按钮侦听以下内容:
spinnerFolder.getOnItemSelectedListener()onItemSelected(spinnerFolder,spinnerFolder.getSelectedView(),spinnerFolder.getSelectedItemPosition(),spinnderFolder.getSelectedItemId());
这就是: - )
I have a spinner control with setOnItemSelectedListener in my app, when I select an item of the spinner, the event onItemSelected will be launched.Now I hope to click a button to launch the onItemSelected event, how can I do? Thanks!
spinnerFolder.setOnItemSelectedListener(new OnItemSelectedListener() {
@Override
public void onItemSelected(AdapterView<?> arg0, View arg1,int arg2, long arg3) {
//Do Business Logic
}
@Override
public void onNothingSelected(AdapterView<?> arg0) {
}
});
解决方案
Just call the following from your button listener:
spinnerFolder.getOnItemSelectedListener().onItemSelected(spinnerFolder, spinnerFolder.getSelectedView(), spinnerFolder.getSelectedItemPosition(), spinnderFolder.getSelectedItemId());
That's all :-)
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