获取Gdk :: Pixbuf上的像素值，使用Gdk :: Cairo设置像素值

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问题描述

我正在使用Gdk::Pixbuf在C ++中显示带有Gdk::Cairo的图像:

I'm using a Gdk::Pixbuf to display an image with Gdk::Cairo in C++ :

virtual bool on_draw(const Cairo::RefPtr<Cairo::Context>& cr)
{
    Glib::RefPtr<Gdk::Pixbuf> image = Gdk::Pixbuf::create_from_file(filename);
    Gdk::Cairo::set_source_pixbuf(cr, image, (width - image->get_width())/2, (height - image->get_height())/2);
    cr->paint();
    /* other displaying stuffs */
}

此图像为黑白图像，我需要带出一些亮度高于特定阈值的像素.为此，我想为那些像素着色.

This image is in B&W and I need to bring out some pixels whose luminance is above a certain threshold. For that, I would like to color those pixels.

首先，我不知道(而且我在网上找不到)如何获取Pixbuf图像中某个像素的亮度.

First, I don't know (and I cannot find on the web) how to get the luminance of a certain pixel of my Pixbuf image.

第二，除了绘制一条长度为1的线(这是种丑陋的解决方案)之外，我没有找到另一种绘制像素的方法.

Second, I don't find another way to draw the pixel than drawing a line of length 1 (which is kind of ugly solution).

您能帮我吗?如果可能的话，我想避免更改库...

Could you help me on this? If possible, I would like to avoid changing library...

谢谢

推荐答案

您可以使用 get pixels() 函数.

You can use the get pixels() function.

void access_pixel( Glib::RefPtr<Gdk::Pixbuf> imageptr, int x, int y )
   {
   if ( !imageptr ) return;
   Gdk::Pixbuf & image = *imageptr.operator->(); // just for convenience

   if ( ! image.get_colorspace() == Gdk::COLORSPACE_RGB ) return;
   if ( ! image.get_bits_per_sample() == 8 ) return;
   if ( !( x>=0 && y>=0 && x<image.get_width() && y<image.get_height() ) ) return;

   int offset = y*image.get_rowstride() + x*image.get_n_channels();
   guchar * pixel = &image.get_pixels()[ offset ]; // get pixel pointer
   if ( pixel[0]>128 ) pixel[1] = 0; // conditionally modify the green channel

   queue_draw(); // redraw after modify
   }

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