本文介绍了使用JSON.NET库在JArray中查找节点(JObject)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在使用JSON.NET库.我已经创建了几个JObjects并将它们添加到JArray中.
I am using JSON.NET library. I have created few JObjects and added them to a JArray.
JArray array = new JArray();
JObject obj = new JObject();
obj.Add(new JProperty("text", "One"));
obj.Add(new JProperty("leaf", false));
array.Add(obj);
obj = new JObject();
obj.Add(new JProperty("text", "Two"));
obj.Add(new JProperty("leaf", false));
array.Add(obj);
obj = new JObject();
obj.Add(new JProperty("text", "Three"));
obj.Add(new JProperty("leaf", true));
array.Add(obj);
现在,我想查找文本(JProperty)为Two
的JObject.如何通过使用JProperty在JArray中找到JObject.
Now I want to find a JObject who's text (JProperty) is Two
. How can I find a JObject within a JArray by using a JProperty.
推荐答案
您可以这样找到它:
JObject jo = array.Children<JObject>()
.FirstOrDefault(o => o["text"] != null && o["text"].ToString() == "Two");
这将在JArray
中找到具有名为text
且值为Two
的属性的第一个JObject
.如果不存在这样的JObject
,则jo
将为空.
This will find the first JObject
in the JArray
having a property named text
with a value of Two
. If no such JObject
exists, then jo
will be null.
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