DataContractJsonSerializer和枚举

问题描述

当我使用DataContractJsonSerializer序列化枚举值时，它将序列化枚举的数值，而不是字符串名称.

When I serialize a enum value using DataContractJsonSerializer, it serializes the numerical value of the enum, not the string name.

IE:

enum foo
{
   bar,
   baz
}

序列化foo.bar的值返回"0"，而不是"bar".

Serializing a value of foo.bar returns "0", not "bar".

相反，我更喜欢它，有没有办法覆盖它?

I'd prefer it the other way around, is there a way to override this?

因为我不想更改序列化程序，所以我使用了一个简单的变通办法.

Because I didn't want to change the serializer, I used a simple workaround hack.

我在类中公开了要序列化的属性，该属性对值调用ToString，即:

I exposed a property in the class to serialize that calls ToString on the value, ie:

// Old
[DataMember]
public EnumType Foo
{
    get { return _foo; }
    set { _foo = value; }
}

// New, I still kept the EnumType but I only serialize the string version

public EnumType Foo
{
    get { return _foo; }
    set { _foo = value; }
}

[DataMember]
public string FooType
{
    get { return _foo.ToString(); }
    private set {}
}

推荐答案

它看起来像这样是设计使然，并且无法更改此行为:

It looks like this is by design and this behavior cannot be changed:

以下是使用替代方法的示例(而且IMO更好且可扩展)实现您所需要的序列化器:

Here's an example using an alternative (and IMO better and more extensible) serializer which achieves what you are looking for:

using System;
using Newtonsoft.Json;

class Program
{
    static void Main(string[] args)
    {
        var baz = Foo.Baz;
        var serializer = new JsonSerializer();
        serializer.Converters.Add(new JsonEnumTypeConverter());
        serializer.Serialize(Console.Out, baz);
        Console.WriteLine();
    }
}

enum Foo
{
    Bar,
    Baz
}

public class JsonEnumTypeConverter : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return objectType == typeof(Foo);
    }
    public override void WriteJson(JsonWriter writer, object value)
    {
        writer.WriteValue(((Foo)value).ToString());
    }

    public override object ReadJson(JsonReader reader, Type objectType)
    {
        return Enum.Parse(typeof(Foo), reader.Value.ToString());
    }
}

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