如何将拖动的项目放入网格?

问题描述

限时删除！！

<mx:DataGrid id="dg1" dataProvider="{cNumbersList}" cornerRadius="3"
    allowMultipleSelection="true"
    change="selectedItem=(event.target as DataGrid).selectedItem.contactName;
            selectedSno=(event.target as DataGrid).selectedItem.contactNo;"
    dropEnabled="true" dragMoveEnabled="true" dragEnabled="true"
    fontWeight="normal">
        <mx:columns>
            <mx:DataGridColumn dataField="contactName" headerText="Name"/>
            <mx:DataGridColumn dataField="contactNo"
                headerText="ContactNo"/>
        </mx:columns>
</mx:DataGrid>

<mx:DataGrid id="dg2" cornerRadius="3" allowMultipleSelection="true"
    visible="false" dataProvider="{}" dropEnabled="true"
    dragMoveEnabled="true" dragEnabled="true" fontWeight="normal">

    <mx:columns>
        <mx:DataGridColumn dataField="contactName" headerText="Name"/>
        <mx:DataGridColumn dataField="contactNo"
            headerText="ContactNo"/>
    </mx:columns>
</mx:DataGrid>

如何将所有拖动的项目放入第二个网格 (dg2)?

How can I get all dragged items in to second grid(dg2)?

推荐答案

如果您想访问从 dg1 放入 dg2 的项目，请按以下步骤操作那个:

If you are looking to access the items dropped into dg2 from dg1, here is how to do that:

var list:ListCollectionView = dg2.dataProvider;
for(i = 0; i < list.length; i++)
  trace(list.getItemAt(i));

顺便说一句，有些东西告诉我这是错误的:

Btw, something tells me that this is wrong:

change="selectedItem=(event.target as DataGrid).selectedItem.contactName;
selectedSno=(event.target as DataGrid).selectedItem.contactNo;"

你想用它完成什么?

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