本文介绍了使用 XPath 获取 XML 子元素的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有这个 XML:

<root>
  <items>
    <item1>
      <tag1>1</tag1>
      <sub>
        <sub1>10 </sub1>
        <sub2>20 </sub2>
      </sub>
    </item1>

    <item2>
      <tag1>1</tag1>
      <sub>
        <sub1> </sub1>
        <sub2> </sub2>
      </sub>
    </item2>
  </items>
</root>

我想获取 item1 元素以及子元素的名称和值.

I want to get the item1 element and the name and values of the child elements.

也就是说,我想得到:tag1 - 1,sub1-10,sub2-20.

That is, i want to get: tag1 - 1,sub1-10,sub2-20.

我该怎么做?到目前为止,我只能获取没有子元素的元素.

How can i do this? so far i can only get elements without children.

推荐答案

import org.w3c.dom.*;
import javax.xml.parsers.*;
import javax.xml.xpath.*;
/**
* File: Ex1.java @author ronda
*/
public class Ex1 {
public static void main(String[] args) throws Exception {
    DocumentBuilderFactory Factory = DocumentBuilderFactory.newInstance();
    DocumentBuilder builder = Factory.newDocumentBuilder();
    Document doc = builder.parse("myxml.xml");

    //creating an XPathFactory:
    XPathFactory factory = XPathFactory.newInstance();
    //using this factory to create an XPath object:
    XPath xpath = factory.newXPath();

    // XPath Query for showing all nodes value
    XPathExpression expr = xpath.compile("//" + "item1" + "/*");
    Object result = expr.evaluate(doc, XPathConstants.NODESET);
    NodeList nodes = (NodeList) result;
    System.out.println(nodes.getLength());
    for (int i = 0; i < nodes.getLength(); i++) {

        Element el = (Element) nodes.item(i);

        System.out.println("tag: " + el.getNodeName());
        // seach for the Text children
        if (el.getFirstChild().getNodeType() == Node.TEXT_NODE)
            System.out.println("inner value:" + el.getFirstChild().getNodeValue());

        NodeList children = el.getChildNodes();
        for (int k = 0; k < children.getLength(); k++) {
            Node child = children.item(k);
            if (child.getNodeType() != Node.TEXT_NODE) {
                System.out.println("child tag: " + child.getNodeName());
                if (child.getFirstChild().getNodeType() == Node.TEXT_NODE)
                    System.out.println("inner child value:" + child.getFirstChild().getNodeValue());;
            }
        }
    }
}
}

我得到这个输出,在名为 myxml.xml 的文件中加载你的问题的 xml:

I get this output loading the xml of your question in file named: myxml.xml:

run:
2
tag: tag1
inner value:1
tag: sub
inner value:

child tag: sub1
inner child value:10
child tag: sub2
inner child value:20

...有点罗嗦,但让我们了解它是如何工作的.PS:我在 here

...a bit wordy, but allow us to understand how it works. PS: I found a good guide in here

这篇关于使用 XPath 获取 XML 子元素的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-24 00:03