如何从数组中的字符串中检索值

问题描述

我正在工作asp.net项目.我上课了，它的返回类型是arraylist，而类返回带有多个值的arrylist，现在我想使用arrylist中的所有值，所以
我以邮件形式发送邮件我希望所有数值都在一个建议中建议我

i m working asp.net project. i had taken class its return type is arraylist and class return arrylist with multiple values now i want use all values from arrylist so
i send mail in mail i want all value in single pls suggest me

推荐答案

ArrayList al = new ArrayList();
al.Add(5);
al.Add("foo");
al.Add(true);
string s="";
foreach (object o in al)
{
  s += o.ToString();
}

如果您有很多项目，请考虑使用 StringBuilder [ ^ ]类.

If you have many items please consider using the StringBuilder[^] class.

http://msdn.microsoft.com上的

public static class ExtensionMethods
{
	// for generic interface IEnumerable<t>     
	public static string ToString<t>(this IEnumerable<t> source, string separator)
	{
		if (source == null)
			throw new ArgumentException("Parameter source can not be null.");

		if (string.IsNullOrEmpty(separator))
			throw new ArgumentException("Parameter separator can not be null or empty.");

		string[] array = source.Where(n => n != null).Select(n => n.ToString()).ToArray();
		return string.Join(separator, array);
	}

	// for interface IEnumerable     
	public static string ToString(this IEnumerable source, string separator)
	{
		if (source == null)
			throw new ArgumentException("Parameter source can not be null.");

		if (string.IsNullOrEmpty(separator))
			throw new ArgumentException("Parameter separator can not be null or empty.");

		string[] array = source.Cast<object>().Where(n => n != null).Select(n => n.ToString()).ToArray();
		return string.Join(separator, array);
	}
}
</t></t></t>

使用此扩展方法的示例:

Example of using this extension method:

ArrayList myArrayList = new ArrayList();
myArrayList.Add("Item1");
myArrayList.Add("Item2");
myArrayList.Add("Item3");
myArrayList.Add("Item4");
myArrayList.Add("Item5");

string myListAsString = myArrayList.ToString("; ");

输出:
Item1；项目2；项目3；项目4； Item5

Output:
Item1; Item2; Item3; Item4; Item5

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