问题描述
我必须从单个C类IP地址对网络进行子网划分.
I have to subnet a network from a single class C IP address.
我已经弄清楚了子网掩码和广播地址(我使用的是子网掩码/28)，但是不知道如何获取网关地址.
I have figured out the subnet mask and the broadcast address (I'm using subnet mask /28) but don't understand how to get the gateway address.
有人可以帮助我吗?
推荐答案
如果子网掩码为255.255.255.248，则掩码位数为5，因此子网数=2.掩码位数的幂数= 2的幂5 = 32个子网，每个子网的主机数=2.功率(未屏蔽位或32-网络位数)= 2功率(32-29)= 8个主机/子网.
If subnet mask is 255.255.255.248 then number of masked bit will be 5, hence number of subnets = 2. The power number of masked bits = 2 the power 5 = 32 subnets, and the number of hosts per subnets = 2. The power (unmasked bit or 32- total number of network bits) = 2 the power (32-29) = 8 host/subnet.
因此:
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1)子网1中的IP从192.168.1.0到192.168.1.7192.168.1.0是子网ID，而192.168.1.7是广播ID.
1) IP's in subnet-1 will be from 192.168.1.0 to 192.168.1.7where 192.168.1.0 will be subnet id and 192.168.1.7 will be broadcast id.
2)子网2中的IP从192.168.1.8到192.168.1.15
2) IP's in subnet-2 will be from 192.168.1.8 to 192.168.1.15
以此类推.........
and so on............
- 32)子网32中的IP将从192.168.1.248到192.168.1.255 .....
网关仅是网络的网关，即该网络的第一个IP地址.
The gateway is only one for a network i.e. the first IP address of that network.
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