本文介绍了来自 mysqli_Query 的回显结果的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我正在制作一个供我自己使用的个人脚本，我需要知道如何回显来自 mysqli_query 的结果.我的代码如下:
I'm making a personal script for my own use, and I need to know how to echo the results from a mysqli_query. My code is as follows:
$conn = mysqli_connect($servername, $username, $password, $dbname);
if(isset($_POST['commercial'])){
if (isset($_POST['0'])){
$sql = "SELECT email FROM CommercialEmails WHERE articleid = '$_POST[article]' AND dripid = 1 AND sent='a'";
$resultsd1 = mysqli_query($conn, $sql);
echo $resultsd1;
}
if (isset ($_POST['1'])){
$sql = "SELECT email FROM CommercialEmails WHERE articleid = '$_POST[article]' AND dripid = 2 AND sent='a'";
$resultsd2 = mysqli_query($conn, $sql);
echo $resultsd2;
}
if (isset($_POST['2'])){
$sql = "SELECT email FROM CommercialEmails WHERE articleid = '$_POST[article]' AND dripid = 3 AND sent='a'";
$resultsd3 = mysqli_query($conn, $sql);
echo $resultsd3;
}
if (isset ($_POST['3'])){
$sql = "SELECT email FROM CommercialEmails WHERE articleid = '$_POST[article]' AND dripid = 4 AND sent='a'";
$resultsd4 = mysqli_query($conn, $sql);
echo $resultsd4;
}
if (isset ($_POST['4'])){
$sql = "SELECT email FROM CommercialEmails WHERE articleid = '$_POST[article]' AND dripid = 5 AND sent='a'";
$resultsd5 = mysqli_query($conn, $sql);
echo $resultsd5;
}
}
?>
推荐答案
如果要输出多行
if (isset($_POST['0'])) {
$sql = "SELECT email FROM CommercialEmails WHERE articleid = '$_POST[article]' AND dripid = 1 AND sent='a'";
$resultsd1 = mysqli_query($conn, $sql);
while ($row = mysqli_fetch_assoc($resultsd1))
{
echo $row['email'];
}
}
如果只有 1 行
if (isset($_POST['0'])){
$sql = "SELECT email FROM CommercialEmails WHERE articleid = '$_POST[article]' AND dripid = 1 AND sent='a' LIMIT 1";
$resultsd1 = mysqli_query($conn, $sql);
$row = mysqli_fetch_assoc($resultsd1);
echo $row['email'];
}
这篇关于来自 mysqli_Query 的回显结果的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！