如何传递变量"$ tid，$ id"；转化为原始功能?

本文介绍了如何传递变量"$ tid，$ id"；转化为原始功能?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

当我在raw函数中调用$id和$tid从mongodb集合的子文档中获取一些数据时，它显示错误these two variables are undefined($tid,$id)吗?

when i call $id and $tid in raw function to fetch some data from sub document of mongodb collection it show me an error these two variables are undefined($tid,$id)?

<?php
$id=IntValue;
$tId=IntValue;
if($tId==0)
{
    $maxPlayers=0;
}
else
{
  $result = DB::collection('PrizeDistributionTemplate')->raw(function($collection)
        {

            return $collection->aggregate(array(
                array(
                    '$match' => array( 'id' => $id,'templates.tId' => $tid)
                ),
                array( '$unwind' => '$templates' ),
                array(
                    '$match' => array( 'id' => $id,'templates.tId' => $tid)
                ),
            ));       
        });

  $result=json_decode(json_encode($result),true);
  $maxPlayers=$result['result'][0]['templates']['maxPlayers'];
  $maxPlayers=intval($maxPlayers)+2;
}
?>

推荐答案

它将与批量添加一起很好地工作，这种方式只需要在数组上创建并传递它即可.

It will work great with bulk addition, this way you just need to create on array and pass it.

$temp = [
   [
     'item' => "envelopes"
   ],
   [
     'item' => "envelopesas"
   ],
   [
     'item' => "lala"
   ]
 ];

 $userData = DB::table('log') - > raw(function ($collection) use($temp) 
 {

   return $collection - > insertMany($temp);
 });

这篇关于如何传递变量"$ tid，$ id"；转化为原始功能?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！

TID