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问题描述
是否有库函数可以查找List1 减去出现在List2 中的元素
?我一直在谷歌搜索,并没有找到太多.
Is there a library function to find List1 minus elements that appear in List2
? I've been googling around and haven't found much.
自己编写它似乎太并不简单.我编写了一个函数来从列表中删除特定元素,但这要简单得多:
It doesn't seem too trivial to write it myself. I've written a function to remove a specific element from a list but that's much more simple:
let rec difference l arg = match l with
| [] -> []
| x :: xs ->
if (x = arg) then difference xs arg
else x :: difference xs arg;;
推荐答案
这行吗?
let diff l1 l2 = List.filter (fun x -> not (List.mem x l2)) l1
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