问题描述
我正在使用jQuery在页面加载时动态添加两个div。这一切都很好,除了,当我点击第一个动态加载的div中的高级选项链接时 - 它执行它的正确行为(滑动第二个动态div),但它重置滚动的窗口回到顶部。我试图专注于我滑开的div的第一个输入元素,但无济于事。
I'm using jQuery to dynamically add two divs on page load. It all works great, except, when I click the "Advanced Options" link in the first dynamically loaded div - it performs it's correct behavior (sliding the second dynamic div), BUT it resets the scroll of the window back to the top. I attempted to focus on the first input element of the div that I slide open, but to no avail.
如何摆脱这种不受欢迎的滚动行为?
How do I get rid of this undesired scrolling behavior?
我已经包含了帮助的代码(尽可能长的啰嗦)
I've included the code to help (as long winded as it is)
<style type="text/css">
.itemcontainer {
background-color:#FFFFCC;
border:1px solid #999999;
height:auto;
margin:1em 0;
overflow:hidden;
position:relative;
width:600px;
}
.itemcontainer .optionpopoutcontainer {
background-color:#44CC55;
bottom:0;
color:#333333;
height:auto;
left:0;
padding:6px;
position:absolute;
width:100%;
}
.itemcontainer .advancedpopoutcontainer {}
</style>
这里是javascript以及HTML
And here's the javascript along with the HTML
<script type="text/javascript">
$(document).ready(function(){
var counter = 0;
//Add the necessary divs to the classes
$(".itemcontainer").each(function(){
var id = $(this).find("input[name='ItemID']").attr('value');
$(this).append("<div class='optionpopoutcontainer' id='quickaddcontainer-" + id + "'></div><div class='advancedpopoutcontainer' id='advancedaddcontainer-" + id + "'></div>");
});
$(".optionpopoutcontainer").css("display", "none"); //used for the sliding up
$(".optionpopoutcontainer").each(function(){
createQuickAddForm($(this), GetID($(this)));
});
$(".advancedpopoutcontainer").css("display", "none"); //used for the sliding up
$(".advancedpopoutcontainer").each(function(){
AddAdvancedOptionsForm($(this), GetID($(this)));
});
$(".cancelButton").click(function(){
var parent = GetParentDiv($(this));
parent.slideToggle();
});
$(".opencontainer").click(function(){
GetParentDiv($(this)).find("div.optionpopoutcontainer").slideToggle(250);
});
$(".quickaddadvoptions").click(function(){
var container = GetParentDiv($(this));
$(container).slideToggle(function(){
var innerContainer = GetParentDiv(container).find("div.advancedpopoutcontainer").slideToggle(250);
});
});
function GetParentDiv(item){
return item.parents('div:eq(0)');
}
function GetID(item){
return item.attr('id').split('-')[1];
}
$("input[name='Date']").each(function(){
$(this).datepicker({dateFormat: 'd MM, y'});
});
});
function createQuickAddForm(item, itemID){
var str = "<form method='post' action='#' id='addform-" + itemID + "'>";
str += "Size: <input id='Size' type='text' value='1' name='Size'/> ";
str += "<input id='ItemID' type='hidden' value='29' name='ItemID'/>";
str += "<input type='submit' value='Log Item'/>";
str += "<a href='#'' class='quickaddadvoptions' id='advancedoptions-" + itemID + "'>Advanced Options</a>";
str += "</form>";
str += "<button class='cancelButton'>Cancel</button>";
item.html(str);
};
function AddAdvancedOptionsForm(containerDiv, itemID){
var str = "<form method='post' action='#' id='addformadv-" + itemID + "'>";
str += "Size: <input id='Size-" + itemID + "' type='text' value='1' name='Size'/><br/>";
str += "Date: <input id='Date-" + itemID + "' type='text' value='" + GetTodaysDate() + "' name='Date'/><br/>";
str += "Note: <input type='textarea' id='Note-" + itemID + "' name='Note' cols='20' name='Note'/><br/>";
str += "<input id='ItemID-" + itemID + "' type='hidden' value='29' name='ItemID'/>";
str += "<input type='submit' value='Log Item'/>";
str += "</form>";
str += "<button class='cancelButton' >Cancel</button>";
containerDiv.html(str);
};
<div class="itemcontainer" name="item1">
<!-- <table> code -->
<button style="float:right" class="opencontainer">slide it</button>
<!-- other <table> code -->
<input type="hidden" value="2" name="ItemID"/>
</div>
推荐答案
尝试阻止超链接的默认操作发生:
Try preventing the default action of your hyperlink from happening:
$(".quickaddadvoptions").click(function(e){
e.preventDefault();
var container = GetParentDiv($(this));
$(container).slideToggle(function(){
var innerContainer = GetParentDiv(container).find("div.advancedpopoutcontainer").slideToggle(250);
});
});
这会阻止浏览器在< a href ='#''你动态加载的div。换句话说,锚点的行为更像是按钮而不是超链接。
That will prevent the browser from jumping when it sees the anchor '#' in <a href='#''
of your dynamically loaded div. In other words, the anchor will behave more like a button than a hyperlink.
请参阅
另请注意,返回false;
在该事件处理程序结束时也应该这样做。
Also note, a return false;
at the end of that event handler should do the trick too.
这篇关于如何防止窗口在jQuery slideToggle()上向上滚动?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!