问题描述
我有以下 GET
REST 方法:
I have the following GET
REST method:
import java.time.OffsetDateTime;
import javax.ws.rs.Consumes;
import javax.ws.rs.DELETE;
import javax.ws.rs.GET;
import javax.ws.rs.HeaderParam;
import javax.ws.rs.POST;
import javax.ws.rs.PUT;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.QueryParam;
import javax.ws.rs.core.Response;
import io.swagger.annotations.Api;
import io.swagger.annotations.ApiOperation;
import io.swagger.annotations.ApiResponse;
import io.swagger.annotations.ApiResponses;
import com.product.rest.api.TransactionsApi;
import com.product.rest.model.Transaction;
@Path("/transactions")
@Api(description = "the transactions API")
@Consumes({ "application/json" })
@Produces({ "application/json" })
public class TransactionsApiImpl extends TransactionsApi {
@GET
@Consumes({ "application/json" })
@Produces({ "application/json" })
@ApiOperation(value = "", notes = "Get all transactions", response = Transaction.class, responseContainer = "List", tags = {})
@ApiResponses(
value = { @ApiResponse(code = 200, message = "OK", response = Transaction.class, responseContainer = "List"),
@ApiResponse(code = 400, message = "Bad Request", response = Transaction.class, responseContainer = "List"),
@ApiResponse(code = 404, message = "Not Found", response = Transaction.class, responseContainer = "List"),
@ApiResponse(code = 500, message = "Internal Server Error", response = Transaction.class, responseContainer = "List") })
@Override
public Response transactionsGet(
@HeaderParam("tok") String tok,
@QueryParam("param1") Integer param1,
@QueryParam("param2") String param2,
@QueryParam("param3") OffsetDateTime param3,
@QueryParam("param4") OffsetDateTime param4,
@QueryParam("param5") Integer param5,
@QueryParam("param6") Integer param6,
@QueryParam("param7") String param7) {
return Response.ok().entity("Success!").build();
}
TransactionsApi
是使用 Swagger Codegen 生成的实现,Transaction
模型类也是如此.我在这个类中还有其他几个函数,但是每当我不注释 GET/transactions
函数时,我都会收到以下错误:
The TransactionsApi
is a generated implementation using Swagger Codegen, as is the Transaction
model class. I have several other functions in this class, but whenever I leave the GET /transactions
function uncommented, I receive the following error:
WARN [Thread-1] (ContextHandler.java:2175) - unavailable
org.glassfish.jersey.server.model.ModelValidationException: Validation of the application resource model has failed during application initialization.
[[FATAL] No injection source found for a parameter of type public javax.ws.rs.core.Response
com.product.rest.impl.v1.TransactionsApiImpl.transactionsGet(java.lang.String,java.lang.Integer,java.lang.String,java.time.OffsetDateTime,java.time.OffsetDateTime,java.lang.Integer,java.lang.Integer,java.lang.String) at index 3.; source='ResourceMethod{httpMethod=GET, consumedTypes=[application/json], producedTypes=[application/json], suspended=false, suspendTimeout=0, suspendTimeoutUnit=MILLISECONDS, invocable=Invocable{handler=ClassBasedMethodHandler{handlerClass=class com.product.rest.impl.v1.TransactionsApiImpl, handlerConstructors=[org.glassfish.jersey.server.model.HandlerConstructor@7df78e88]}, definitionMethod=public javax.ws.rs.core.Response
我发现的所有其他类似问题都与 MultiPart Data
和文件上传有关,而我正在发出一个简单的 GET
请求.其他同样使用javax.ws.rs.code.Response
类的函数没有这个问题,服务器正常启动.
All other similar questions I have found had to do with MultiPart Data
and file uploading, whereas I am making a simple GET
request. Other functions that also use the javax.ws.rs.code.Response
class do not have this issue and the server starts normally.
我注意到只要 OffsetDateTime
类在参数中(即 param3
和 param4
)就会出现问题,但我一直无法找出原因.此外,OffsetDateTime
是由 Swagger Codegen 选择的,我不愿意更改它,看看我以后每次重新生成源时都必须更改每个派生文件.
I have noticed that the problem happens whenever the OffsetDateTime
class is in the parameters (i.e. param3
and param4
), but I have been unable to find out why. Moreover, OffsetDateTime
was chosen by Swagger Codegen and I am reluctant to change it seeing how I will have to change every derived file afterwards whenever I regenerate my sources.
有没有人在使用 REST 服务和 OffsetDateTime
之前遇到过这个问题?
Has anyone had this issue before with REST services and OffsetDateTime
?
推荐答案
有关系.该错误是您在 Jersey 无法验证资源模型时遇到的一般错误.资源模型的一部分是方法参数.Jersey 有一个系统可以知道哪些参数可以处理,哪些不能处理.在您的情况下,它不知道如何处理 OffsetDateTime
.
It's related. The error is a general error you get when Jersey can't validate the resource model. Part of the resource model is the method parameters. Jersey has a system for knowing which parameters it will be able to process and which ones it won't. In your case, it doesn't know how to process the OffsetDateTime
.
为了能够将非基本类型用作@QueryParam
s(以及所有其他 @XxxParams
,例如 @PathParam
和@FormParam
等):
There are a set of rules that you need to follow in order to able to use non basic types as @QueryParam
s (and all other @XxxParams
such as @PathParam
and @FormParam
, etc.):
- 成为原始类型
- 有一个接受单个
String
参数的构造函数 - 有一个名为
valueOf
或fromString
的静态方法,它接受单个字符串参数(例如,请参见Integer.valueOf(String)
) - 拥有
ParamConverterProvider
JAX-RS 扩展 SPI 的注册实现,它返回一个能够对类型进行从字符串"转换的ParamConverter
实例. - 成为
List
、Set
或SortedSet
,其中T
满足2、3 或 4 以上.生成的集合是只读的.
- Be a primitive type
- Have a constructor that accepts a single
String
argument - Have a static method named
valueOf
orfromString
that accepts a single String argument (see, for example,Integer.valueOf(String)
) - Have a registered implementation of
ParamConverterProvider
JAX-RS extension SPI that returns aParamConverter
instance capable of a "from string" conversion for the type. - Be
List<T>
,Set<T>
orSortedSet<T>
, whereT
satisfies 2, 3 or 4 above. The resulting collection is read-only.
所以在这个 OffsetDateTime
的例子中,沿着列表往下走;它不是原始的;它没有 String 构造函数;它没有静态的 valueOf
或 fromString
So in this case of OffsetDateTime
, going down the list; it's not a primitive; it doesn't have a String constructor; it doesn't have a static valueOf
or fromString
所以基本上,剩下的唯一选择就是为它实现一个 ParamConverter/ParamConverterProvider
.基本设置如下
So basically, the only option left is to implement a ParamConverter/ParamConverterProvider
for it. The basic set up looks like
@Provider
public class OffsetDateTimeProvider implements ParamConverterProvider {
@Override
public <T> ParamConverter<T> getConverter(Class<T> clazz, Type type, Annotation[] annotations) {
if (clazz.getName().equals(OffsetDateTime.class.getName())) {
return new ParamConverter<T>() {
@SuppressWarnings("unchecked")
@Override
public T fromString(String value) {
OffsetDateTime time = ...
return (T) time;
}
@Override
public String toString(T time) {
return ...;
}
};
}
return null;
}
}
Jersey 将向您传递查询参数的 String 值,您的工作是创建它并返回它.
Jersey will pass you the String value of the query parameter, and it's your job to to create it and return it.
然后只需向应用程序注册 OffsetDateTimeProvider
.如果您使用包扫描,则应从 @Provider
注释中自动获取并注册.
Then just register the OffsetDateTimeProvider
with the application. If you're using package scanning, it should be picked up and registered automatically from the @Provider
annotation.
我不使用 Swagger,所以我不知道他们是否已经提供了已经实现的类似的东西,但他们会为你生成这个似乎很奇怪,而且没有办法让它工作.我知道 Jersey 3 将支持 Java 8,但谁知道什么时候会发布.
I don't use Swagger, so I don't know if they already provide something like this already implemented, but it seems odd that they would generate this for you, and not have a way to make it work. I know Jersey 3 will have Java 8 support out the box, but who know when the heck that's gonna be released.
这篇关于OffsetDateTime 产生“未找到类型为 public javax.ws.rs.core.response 的参数的注入源";在 GET 方法中的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!