Java四舍五入

问题描述

我如何将 numberGrade 的值向上调整，如果它是 89.5，它会变为 90.numberGrade 被视为双精度值，但将其设为 int 并不会对其进行四舍五入.

How can I rould the value of the numberGrade up so if it is 89.5 it goes to 90. numberGrade is taken in as a double but making it a int does not round it up or down.

public class GradeReporter
{
    // The limit is the inclusive lower limit for each letter
    // grade -- this means that 89.5 is an 'A' not a 'B'
    public static final double A_LIMIT = 90;
    public static final double B_LIMIT = 80;
    public static final double C_LIMIT = 70;
    public static final double D_LIMIT = 60;
    public static final double F_LIMIT = 60;

    /** Converts a numeric grade into a letter grade. Grades should be rounded to
     *  nearest whole number
     *
     * @param a numeric grade in the range of 0 to 100
     * @returns a letter grade based on the numeric grade, possible grades are A, B, C, D and F.
     */
    public char letterGrade(double numberGrade)
    {
        int grade = int(numberGrade);
        if (grade >= A_LIMIT)
            letterGrade = 'A';
        else if (grade >= B_LIMIT)
            letterGrade = 'B';
        else if (grade >= C_LIMIT)
            letterGrade = 'C';
        else if (grade >= D_LIMIT)
            letterGrade = 'D';
        else if (grade < F_LIMIT)//4
            letterGrade = 'F';
        return letterGrade;
    }

推荐答案

要将向上舍入，您可以使用 Math.ceil(numberGrade).要四舍五入到最接近的整数，请使用 Math.round(numberGrade).

To round up, you can use Math.ceil(numberGrade). To round to the nearest integer, use Math.round(numberGrade).

参见:数学 班级

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