将数字四舍五入为最接近的5的倍数

问题描述

有谁知道如何将数字四舍五入到最接近的5的倍数？我发现了一个算法将它四舍五入到最接近的10的倍数，但我找不到这个。

Does anyone know how to round up a number to its nearest multiple of 5? I found an algorithm to round it to the nearest multiple of 10 but I can't find this one.

这是10个。

double number = Math.round((len + 5)/ 10.0) * 10.0;

推荐答案

int roundUp(int n) {
    return (n + 4) / 5 * 5;
}

注意 - YankeeWhiskey的答案是四舍五入到最接近的倍数，这是四舍五入。如果您需要修改负数，则需要进行修改。请注意，整数除法后跟相同数字的整数乘法是向下舍入的方式。

Note - YankeeWhiskey's answer is rounding to the closest multiple, this is rounding up. Needs a modification if you need it to work for negative numbers. Note that integer division followed by integer multiplication of the same number is the way to round down.

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