使用基础实体的Hibernate Annotation

问题描述

在我的项目中，我有一个名为BaseEntity的POJO，如下所示。

  class BaseEntity {
 private int id ; 
 public void setId（int id）{
 this.id = id; 
} 
 public int getId（）{
 return id; 
 
 
 
 
 
 
 $ b 
还有一组POJO实体类，如Movie，演员，...  
 
 
  class Movie扩展BaseEntity {
私有字符串名称; 
 private int年; 
 private int durationMins; 
 // getters和setters 
} 
  
我只使用BaseEntity将其用作某些界面中的占位符。我从来不需要存储BaseEntity对象。我只需要存储从BaseEntity扩展的实体对象。我应该如何注释这些类，以便从BaseEntity扩展的每个实体获得一个表。对于电影来说，它应该像（id，name，year，durationMins）。
解决方案
我在完全无关的帖子中找到了答案。我只需要将BaseEntity注释为@MappedSuperclass。 
  @MappedSuperclass $ b $ class BaseEntity {
 @Id 
 private int id; 
 //获得者和设置者。 
} 
 @Entity 
类Movie扩展BaseEntity {
 @Column 
私有字符串名称; 
 @Column 
 private int year; 
 @Column 
 private int durationMins; 
 // getters and setters 
} 
  
 
In my project I have a POJO called BaseEntity as shown below.
class BaseEntity{
    private int id;
    public void setId(int id){
        this.id=id;
    }
    public int getId(){
        return id;
    }
}
And a set of other POJO entity classes like Movie, Actor,...
class Movie extends BaseEntity{
    private String name;
    private int year;
    private int durationMins;
    //getters and setters
}
I'm using BaseEntity only for using it as a place holder in some interfaces. I never have to store a BaseEntity object. I have to store only the entity objects extended from BaseEntity. How should I annotate these classes so that I get one table per entity extended from the BaseEntity. For movie it should be like (id, name, year, durationMins).
 解决方案 
I found the answer in a totally unrelated post. I just have to annotate BaseEntity as @MappedSuperclass. The following code done what I needed.
@MappedSuperclass
class BaseEntity {
    @Id
    private int id;
    //getters and setters.
}
@Entity
class Movie extends BaseEntity {
    @Column
    private String name;
    @Column
    private int year;
    @Column
    private int durationMins;
    //getters and setters
}
                        
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