本文介绍了正确的YUV422到RGB转换的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我一直在试图把一个YUV422转换成RGB转换问题大约一个星期。我访问过许多不同的网站，并从每一个得到不同的公式。如果任何人有任何建议，我会很高兴听到他们。下面的公式给了我一个图像与或整体紫色或绿色的色调。到目前为止，我还没有找到一个公式，让我得到一个正确的RGB图像。
I've been trying to tackle a YUV422 into a RGB conversion problem for about a week. I've visited many different websites and have gotten different formulas from each one. If anyone else has any suggestions I would be glad to hear about them. The formulas below give me an image with either and overall purple or a green hue in them. As of this moment I haven't been able to find a formula that allows me to get back a proper RGB image. I have include all my various chunks of code below.
//for(int i = 0; i < 1280 * 720 * 3; i=i+3)
//{
// /*m_RGB->imageData[i] = pData[i] + pData[i+2]*((1 - 0.299)/0.615);
// m_RGB->imageData[i+1] = pData[i] - pData[i+1]*((0.114*(1-0.114))/(0.436*0.587)) - pData[i+2]*((0.299*(1 - 0.299))/(0.615*0.587));
// m_RGB->imageData[i+2] = pData[i] + pData[i+1]*((1 - 0.114)/0.436);*/
// m_RGB->imageData[i] = pData[i] + 1.403 * (pData[i+1] - 128);
// m_RGB->imageData[i+1] = pData[i] + 0.344 * (pData[i+1] - 128) - 0.714 * (pData[i+2] - 128);
// m_RGB->imageData[i+2] = pData[i] + 1.773 * (pData[i+2] - 128);
//}
for(int i = 0, j=0; i < 1280 * 720 * 3; i+=6, j+=4)
{
/*m_RGB->imageData[i] = pData[j] + pData[j+3]*((1 - 0.299)/0.615);
m_RGB->imageData[i+1] = pData[j] - pData[j+1]*((0.114*(1-0.114))/(0.436*0.587)) - pData[j+3]*((0.299*(1 - 0.299))/(0.615*0.587));
m_RGB->imageData[i+2] = pData[j] + pData[j+1]*((1 - 0.114)/0.436);
m_RGB->imageData[i+3] = pData[j+2] + pData[j+3]*((1 - 0.299)/0.615);
m_RGB->imageData[i+4] = pData[j+2] - pData[j+1]*((0.114*(1-0.114))/(0.436*0.587)) - pData[j+3]*((0.299*(1 - 0.299))/(0.615*0.587));
m_RGB->imageData[i+5] = pData[j+2] + pData[j+1]*((1 - 0.114)/0.436);*/
/*m_RGB->imageData[i] = pData[j] + 1.403 * (pData[j+3] - 128);
m_RGB->imageData[i+1] = pData[j] + 0.344 * (pData[j+1] - 128) - 0.714 * (pData[j+3] - 128);
m_RGB->imageData[i+2] = pData[j] + 1.773 * (pData[j+1] - 128);
m_RGB->imageData[i+3] = pData[j+2] + 1.403 * (pData[j+3] - 128);
m_RGB->imageData[i+4] = pData[j+2] + 0.344 * (pData[j+1] - 128) - 0.714 * (pData[j+3] - 128);
m_RGB->imageData[i+5] = pData[j+2] + 1.773 * (pData[j+1] - 128);*/
BYTE Cr = pData[j+3] - 128;
BYTE Cb = pData[j+1] - 128;
/*m_RGB->imageData[i] = pData[j] + Cr + (Cr >> 2) + (Cr >> 3) + (Cr >> 5);
m_RGB->imageData[i+1] = pData[j] - ((Cb >> 2) + (Cb >> 4) + (Cb >> 5)) - ((Cr >> 1) + (Cr >> 3) + (Cr >> 4) + (Cr >> 5));
m_RGB->imageData[i+2] = pData[j] + Cb + (Cb >> 1) + (Cb >> 2) + (Cb >> 6);
m_RGB->imageData[i+3] = pData[j+2] + Cr + (Cr >> 2) + (Cr >> 3) + (Cr >> 5);
m_RGB->imageData[i+4] = pData[j+2] - ((Cb >> 2) + (Cb >> 4) + (Cb >> 5)) - ((Cr >> 1) + (Cr >> 3) + (Cr >> 4) + (Cr >> 5));
m_RGB->imageData[i+5] = pData[j+2] + Cb + (Cb >> 1) + (Cb >> 2) + (Cb >> 6);*/
/*int R1 = clamp(1 * pData[j] + 0 * Cb + 1.4 * Cr, 0, 255), R2 = clamp(1 * pData[j+2] + 0 * Cb + 1.4 * Cr, 0, 255);
int G1 = clamp(1 * pData[j] - 0.343 * Cb - 0.711 * Cr, 0, 255), G2 = clamp(1 * pData[j+2] - 0.343 * Cb - 0.711 * Cr, 0, 255);
int B1 = clamp(1 * pData[j] + 1.765 * Cb + 0 * Cr, 0, 255), B2 = clamp(1 * pData[j+2] + 1.765 * Cb + 0 * Cr, 0, 255);*/
/*int R1 = clamp(pData[j] + 1.403 * (pData[j+3] - 128), 0, 255), R2 = clamp(pData[j+2] + 1.403 * (pData[j+3] - 128), 0, 255);
int G1 = clamp(pData[j] + 0.344 * (pData[j+1] - 128) - 0.714 * (pData[j+3] - 128), 0, 255), G2 = clamp(pData[j+2] + 0.344 * (pData[j+1] - 128) - 0.714 * (pData[j+3] - 128), 0, 255);
int B1 = clamp(pData[j] + 1.773 * (pData[j+1] - 128), 0, 255), B2 = clamp(pData[j+2] + 1.773 * (pData[j+1] - 128), 0, 255);*/
int R1 = clamp((298 * (pData[j] - 16) + 409 * (pData[j+3] - 128) + 128) >> 8, 0, 255), R2 = clamp((298 * (pData[j+2] - 16) + 409 * (pData[j+3] - 128) + 128) >> 8, 0, 255);
int G1 = clamp((298 * (pData[j] - 16) - 100 * (pData[j+1] - 128) - 208 * (pData[j+3] - 128) + 128) >> 8, 0, 255), G2 = clamp((298 * (pData[j+2] - 16) - 100 * (pData[j+1] - 128) - 208 * (pData[j+3] - 128) + 128) >> 8, 0, 255);
int B1 = clamp((298 * (pData[j] - 16) + 516 * (pData[j+1] - 128) + 128) >> 8, 0, 255), B2 = clamp((298 * (pData[j+2] - 16) + 516 * (pData[j+1] - 128) + 128) >> 8, 0, 255);
//printf("R: %d, G: %d, B: %d, R': %d, G': %d, B': %d \n", R1, G1, B1, R2, G2, B2);
m_RGB->imageData[i] = (char)R1;
m_RGB->imageData[i+1] = (char)G1;
m_RGB->imageData[i+2] = (char)B1;
m_RGB->imageData[i+3] = (char)R2;
m_RGB->imageData[i+4] = (char)G2;
m_RGB->imageData[i+5] = (char)B2;
/*m_RGB->imageData[i] = (char)(clamp(1.164 * (pData[j] - 16) + 1.793 * (Cr), 0, 255));
m_RGB->imageData[i+1] = (char)(clamp(1.164 * (pData[j] - 16) - 0.534 * (Cr) - 0.213 * (Cb), 0, 255));
m_RGB->imageData[i+2] = (char)(clamp(1.164 * (pData[j] - 16) + 2.115 * (Cb), 0, 255));
m_RGB->imageData[i+3] = (char)(clamp(1.164 * (pData[j+2] - 16) + 1.793 * (Cr), 0, 255));
m_RGB->imageData[i+4] = (char)(clamp(1.164 * (pData[j+2] - 16) - 0.534 * (Cr) - 0.213 * (Cb), 0, 255));
m_RGB->imageData[i+5] = (char)(clamp(1.164 * (pData[j+2] - 16) + 2.115 * (Cb), 0, 255));*/
}
任何帮助都非常感激。
推荐答案
有些线索可以帮助你：
你对Cb感到困惑。
假设UYVY / 422
Assuming UYVY/422
Y1 = data[j+0];
Cr = data[j+1];
Y2 = data[j+2];
Cb = data[j+3];
您的转换计算较为模糊，不适用于HD。
Your conversion calculation are wierd, and incorrect for HD.
对于SD
R = max(0, min(255, 1.164(Y - 16) + 1.596(Cr - 128)));
G = max(0, min(255, 1.164(Y - 16) - 0.813(Cr - 128) - 0.391(Cb - 128)));
B = max(0, min(255, 1.164(Y - 16) + 2.018(Cr - 128)));
适用于HD
R = max(0, min(255, 1.164(Y - 16) + 1.793(Cr - 128)));
G = max(0, min(255, 1.164(Y - 16) - 0.534(Cr - 128) - 0.213(Cb - 128)));
B = max(0, min(255, 1.164(Y - 16) + 2.115(Cr - 128)));
您可以使用 ConvertFrame 部分Decklink SDK。
You could simply use ConvertFrame which is a part of the Decklink SDK.
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