本文介绍了移位的奇怪行为的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
无法理解这种移位的行为:
Can't understand behavior of this bit shift:
int container = 1;
cout<<(container>>32)<<endl;
如果是逻辑移位，则输出应为0，但应为1，就像循环移位一样.在查看反汇编时，我看到所使用的命令是SAR.请向我解释这种行为.
If it's logical shift the output should be 0, but it's 1 instead, as if it was cyclic shift. When looking at disassembly I see that command used is SAR. Please explain this behavior to me.
推荐答案
您将32位数字移位了32，这导致行为未定义，结果1是一个巧合.
You shifted a 32-bit number by 32, which results in undefined behavior, and the resulting 1 is a coincidence.
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