反转两位数后

问题描述

我正在c#中使用此代码

i am using this code in c#

char[] arr = textBox1.Text.ToCharArray();
   Array.Reverse(arr);
   textBox2.Text=new string(arr);

它会将整个字符串abcd反转为dcba，但我想像badc一样反转它，但是此代码不适用于这种情况...
有人可以帮我吗?

it will reverse tha whole string abcd as dcba but i want to reverse it like badc but this code is not working for this case...
can anyone help me?

推荐答案

1 2 3 4 5

成为

5 4 3 2 1

如果您想要特殊交换"，则必须自己实现-并不是那么简单...

If you want a "special swap then you have to implement it yourself - which is not so simple...

string input = "AbCdEfGh";
StringBuilder sb = new StringBuilder(input.Length);
for (int i = 0; i < input.Length / 2; i++)
    {
    int index = i * 2;
    sb.Append(input[index + 1]);
    sb.Append(input[index]);
    }
if (input.Length % 2 == 1)
    {
    sb.Append(input[input.Length - 1]);
    }
string output = sb.ToString();

string s = "AbCdEfG";
char[] chars = s.ToCharArray();
//Create keys array from the indices of characters 0 1 2 3 4 5 6 =>  2 1 4 3 6 5 8
int[] keys = Array.ConvertAll(chars, x => {int ind = s.IndexOf(x); return ind % 2 == 0 ? ind+2 : ind;});
//Use the Sort method of Array class to sort chars array using keys array
Array.Sort(keys,chars);
string alternateReversedString = new string(chars);

//Or 

string s = "AbCdEfG";
char[] chars = s.ToCharArray();
//swap adjacent characters
char temp;
for(int i = 1; i < chars.Length; i += 2){
   temp=chars[i];
   chars[i]=chars[i-1];
   chars[i-1]=temp;
}
string alternateReversedString = new string(chars);

//The alternateReversedString will be
//bAdCfEG

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