在JavaScript中删除字符串中的重音符号/变音符号

问题描述

如何从字符串中删除突出的字符？
特别是在IE6中，我有这样的东西：

How do I remove accentuated characters from a string?Especially in IE6, I had something like this:

accentsTidy = function(s){
    var r=s.toLowerCase();
    r = r.replace(new RegExp(/\s/g),"");
    r = r.replace(new RegExp(/[àáâãäå]/g),"a");
    r = r.replace(new RegExp(/æ/g),"ae");
    r = r.replace(new RegExp(/ç/g),"c");
    r = r.replace(new RegExp(/[èéêë]/g),"e");
    r = r.replace(new RegExp(/[ìíîï]/g),"i");
    r = r.replace(new RegExp(/ñ/g),"n");
    r = r.replace(new RegExp(/[òóôõö]/g),"o");
    r = r.replace(new RegExp(/œ/g),"oe");
    r = r.replace(new RegExp(/[ùúûü]/g),"u");
    r = r.replace(new RegExp(/[ýÿ]/g),"y");
    r = r.replace(new RegExp(/\W/g),"");
    return r;
};

但IE6让我感到烦恼，似乎它不喜欢我的正则表达式。

but IE6 bugs me, seems it doesn't like my regular expression.

推荐答案

使用ES2015 / ES6 ，

With ES2015/ES6 String.Prototype.Normalize(),

const str = "Crème Brulée"
str.normalize('NFD').replace(/[\u0300-\u036f]/g, "")
> 'Creme Brulee'

这里发生了两件事：

1. normalize（）转到 NFD Unicode普通表单将合并的字形分解为简单的组合。 Crème的è最终表示为 e + 。


2. 使用正则表达式以匹配U + 0300→U + 036F范围，它现在是微不足道的 g 自由地摆脱变音符号，其中Unicode标准可以方便地分组为 Unicode块。

1. normalize()ing to NFD Unicode normal form decomposes combined graphemes into the combination of simple ones. The è of Crème ends up expressed as e + ̀.
2. Using a regex character class to match the U+0300 → U+036F range, it is now trivial to globally get rid of the diacritics, which the Unicode standard conveniently groups as the Combining Diacritical Marks Unicode block.

查看性能测试评论。

或者，如果您只想要排序

有足够的支持，一个polyfill也可以但我还没有测试过。

Intl.Collator has sufficient support ~85% right now, a polyfill is also available here but I haven't tested it.

const c = new Intl.Collator();
['creme brulee', 'crème brulée', 'crame brulai', 'crome brouillé',
'creme brulay', 'creme brulfé', 'creme bruléa'].sort(c.compare)
[ 'crame brulai','creme brulay','creme bruléa','creme brulee',
'crème brulée','creme brulfé','crome brouillé' ]


['creme brulee', 'crème brulée', 'crame brulai', 'crome brouillé'].sort((a,b) => a>b)
["crame brulai", "creme brulee", "crome brouillé", "crème brulée"]

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