我正在尝试转换两个持续时间，但是由于一个是 datetime.timedelta TypeError c $ c>，其中一个是 datetime.time ：
I am trying to convert two "durations", however I am currently receiving a TypeError due to one being a datetime.timedelta and one being a datetime.time:
TypeError: unorderable types: datetime.time() <= datetime.timedelta()
什么是有效的将 datetime.time 转换为 datetime.timedelta 的方法？
What is an efficient way to convert a datetime.time to a datetime.timedelta?
我已经检查了，但没有内置的方法可在这两种类型之间进行转换。
I have checked the docs and there is no built-in method for conversion between these two types.
datetime.time（）不是持续时间，而是一天中的某个时间点。如果要将其解释为持续时间，则将其转换为午夜以来的持续时间：
datetime.time() is not a duration, it is a point in a day. If you want to interpret it as a duration, then convert it to a duration since midnight:
datetime.combine(date.min, timeobj) - datetime.min
Demo：
Demo:
>>> from datetime import datetime, date, time
>>> timeobj = time(12, 45)
>>> datetime.combine(date.min, timeobj) - datetime.min
datetime.timedelta(0, 45900)
您可能首先需要检查如何获取 datetime.time（）对象，也许到<$ c的路径更短$ c> timedelta（）来自您的输入数据？例如，请勿将 datetime.time.strptime（）用于持续时间。
You may need to examine how you get the datetime.time() object in the first place though, perhaps there is a shorter path to a timedelta() from the input data you have? Don't use datetime.time.strptime() for durations, for example.
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