问题描述
因此,我有一些Java代码可以广泛使用编译正常的泛型.我将其移植到C#,如下所示:
So I have some Java code that makes extensive use of generics that compiles just fine. I ported it over to C# as follows:
interface IFoo1 { }
interface IFoo2 { }
interface IBar<T, K>
where T : IFoo1
where K : IFoo2 {
List<T> GetFoo1s();
void AddAFoo1(T foo1);
List<K> GetFoo2s();
void AddAFoo2(K foo2);
}
interface IBlip<T>
where T : IBar<IFoo1, IFoo2> {
T DoBlip(string input);
void DoBlip2(T input);
}
interface IConverter<T, K>
where T : IBar<IFoo1, IFoo2>
where K : IBar<IFoo1, IFoo2> {
K Convert(T input);
}
class FooA1 : IFoo1 { }
class FooB1 : IFoo1 { }
class FooA2 : IFoo2 { }
class FooB2 : IFoo2 { }
class BarA : IBar<FooA1, FooA2> {
public List<FooA1> GetFoo1s() { return null; }
public void AddAFoo1(FooA1 foo1) { }
public List<FooA2> GetFoo2s() { return null; }
public void AddAFoo2(FooA2 foo2) { }
}
class BarB : IBar<FooB1, FooB2> {
public List<FooB1> GetFoo1s() { return null; }
public void AddAFoo1(FooB1 foo1) { }
public List<FooB2> GetFoo2s() { return null; }
public void AddAFoo2(FooB2 foo2) { }
}
class BlipA : IBlip<BarA> {
public BarA DoBlip(string input) { return null; }
public void DoBlip2(BarA input) { }
}
class BlipB : IBlip<BarB> {
public BarB DoBlip(string input) { return null; }
public void DoBlip2(BarB input) { }
}
class ConverterImplementation : IConverter<BarA, BarB> {
public BarB Convert(BarA input) {
return null;
}
}
当我对此进行编译时,它抱怨说,例如,使用ConverterImplementation,BarA无法隐式转换为IBar.我猜这里根本没有我想要的东西.有人可以阐明一下吗?谢谢.
When I compile this, it complains that, for example, with the ConverterImplementation, that BarA cannot be implicitly converted to IBar. I guess there's something that I'm fundamentally missing here. Could someone shed some light on it? Thanks.
推荐答案
默认情况下,通用类型参数既不是协变也不是协变,但可以通过"in"和"out"关键字使它们成为一个或另一个.
Generic type parameters are by default neither contravariant nor covariant, but can be made one or the other via the "in" and "out" keywords.
在IBar< T,K>的情况下,两个类型参数都用作输入和输出,因此您不能使它们成为协变或协变的.如果将其重构为两个接口,一个在其中T仅用于输入而K仅用于输出,而在其中T仅用于输出而K仅用于输入的接口,则可以使每个类型参数基于协变或互变
In the case of IBar<T, K>, both type parameters are used as both inputs and outputs, so you cannot make them either contravariant or covariant. If you refactored it into two interfaces, one in which T is used only for input and K only for output, and one in which T is used only for output and K only for input, then you could make each type parameter covariant or contravariant based on its usage.
这篇关于泛型,协方差/协方差等的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!