问题描述
我有一种颜色想要转换为不同的颜色空间.是否可以直接在 cv::Vec3f
上使用 cvtColor
而无需创建 1x1 cv::Mat
并用该像素填充它,使用cvtColor
在 cv::Mat
上,然后从输出中获取唯一的像素?我尝试了以下方法,但似乎不喜欢传递向量.
I have a color that I want to convert to a different color space. Is it possible to use cvtColor
on a cv::Vec3f
directly without creating a 1x1 cv::Mat
and populating it with that pixel, using cvtColor
on the cv::Mat
, then getting the only pixel out of the output? I have tried the following, but it doesn't seem to like getting passed a vector.
有什么建议吗?
#include <iostream>
#include <opencv2/opencv.hpp>
int main(int, char*[])
{
cv::Vec3f hsv;
hsv[0] = .9;
hsv[1] = .8;
hsv[2] = .7;
std::cout << "HSV: " << hsv << std::endl;
cv::Vec3b bgr;
cvtColor(hsv, bgr, CV_HSV2BGR); // OpenCV Error: Assertion failed (scn == 3 && (dcn == 3 || dcn == 4) && (depth == CV_8U || depth == CV_32F)) in cvtColor
std::cout << "BGR: " << bgr << std::endl;
return EXIT_SUCCESS;
}
我也试过这个,但得到一个不同的错误:
I also tried this, but get a different error:
#include <iostream>
#include <opencv2/opencv.hpp>
int main(int, char*[])
{
cv::Mat_<cv::Vec3f> hsv(cv::Vec3f(0.7, 0.7, 0.8));
std::cout << "HSV: " << hsv << std::endl;
cv::Mat_<cv::Vec3b> bgr;
cvtColor(hsv, bgr, CV_HSV2BGR); // OpenCV Error: Assertion failed (!fixedType() || ((Mat*)obj)->type() == mtype) in create
std::cout << "BGR: " << bgr << std::endl;
return EXIT_SUCCESS;
}
推荐答案
您的第二种方法是正确的,但是您在 cvtColor
中有不同类型的源和目标,这会导致错误.
Your second approach is correct, but you have source and destination of different types in cvtColor
, and that causes the error.
确保 hsv
和 bgr
的类型相同,CV_32F
在这里:
Be sure to have both hsv
and bgr
of the same type, CV_32F
here:
#include <opencv2/opencv.hpp>
#include <iostream>
int main()
{
cv::Mat3f hsv(cv::Vec3f(0.7, 0.7, 0.8));
std::cout << "HSV: " << hsv << std::endl;
cv::Mat3f bgr;
cvtColor(hsv, bgr, CV_HSV2BGR);
std::cout << "BGR: " << bgr << std::endl;
return 0;
}
为了简洁起见,您可以使用 Mat3f
.这只是一个类型定义:
You can use Mat3f
for brevity. It's just a typedef:
typedef Mat_<Vec3f> Mat3f;
这篇关于使用 cvtColor 转换单一颜色的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!