是“全球"的makefile变量与特定于目标的变量不同吗?

问题描述

来自文档:

因此，给了一个makefile:

So, given a makefile:

% : foo += 1

all : x;

x ::
    @echo '$(foo)'

foo := 2

正在运行，我得到:

And running, I get:

2 1 1

仔细看一下上面的引用:

Taking a closer look at the quote above:

不可能解释 特定于目标的 定义，例如:% : foo += 1，最终会在其值中包含 include ， 全局"值(即非目标值或特定于模式的值):2.

It is impossible to explain how a target-specific definition like: % : foo += 1, will end up to include in its value, the "global" (i.e. not target or pattern-specific) value: 2.

当我们稍后看时，在上面的引文中很难证明这一点:

Much harder to justify it, when we look later, in the quote above:

如果它们是不同的"，那么Make最终会为目标all扩展，该值是取自全局"值以及特定于目标的值的沙拉"值定义?

If, they are that "distinct", how come Make ends up expanding for the target all, a value that is a "salad" of values taken from the "global", and as well from the target-specific definition?

使用什么方法来产生值2 1 1，因为显然，值1 产生了在上面的生成文件中的值2.

And what methodology did Make use to bring about the value 2 1 1, because clearly, the value 1 proceeds the value 2 in the makefile above.

推荐答案

我相信您只是误解了"distinct"的含义.它不是两个变量.通过以下片段两个变量不必具有相同的风格"来阐明其含义.这才是重点.全局变量foo和特定于目标的变量foo是两个不同的(但在扩展时组合).

I believe you are simply misunderstanding what the meaning of "distinct" meant there. It did not mean that they are two different variables. The meaning was clarified by the following fragment "the two variables do not have to have the same flavor". That's the point. The global variable foo and the target-specific variable foo are two different (but combined when expanded) variables.

请记住，您得到的输出正是您所期望的.

With that in mind the output you get is exactly what you'd expect.

分配给foo的第一项是全局分配中的值2.

The first thing assigned to foo is the value 2 from the global assignment.

仅在目标处理期间之后(foo += 1分配已处理)(两次，一次对all，一次对x).

Only after that, during the target processing, is the foo += 1 assignment processed (twice, once for all and once for x).

完全符合您的情况2 1 1.

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