如何通过在Android中快速单击两次按钮来防止运行双重代码

问题描述

如果我快速点击我的Android应用中的按钮，则它背后的代码似乎运行了两次.如果我两次单击菜单按钮，则必须启动onclick的活动将开始两次，并且必须退出两次.

If i click fast to my button in my Android app, it seems that code behind it runs twice.If i click my menu button twice the activity that has to be launch onclick just starts twice and i have to quit from it twice.

这真的很烦人，因为如果我单击菜单按钮的速度太快，我可以在后台加载一大堆活动，并且必须逐个退出，所以这显然是我想要的应用程序的错误状态解决这个问题.

This is really annoying because if i click too fast for menu buttons i can load up a whole bunch of activities in the background and i must quit them one by one, so this is clearly a buggy state of my app i want to fix this.

该问题我该怎么办?

我使用简单的onClickListeners和Buttons

I use simple onClickListeners and Buttons

关于答案和评论，我的菜单按钮如下所示:

Regarding to answers and comments my menu buttons look like this:

top20Button.setOnClickListener(new OnClickListener()
{
    public void onClick(View v)
    {
        favButton.setClickable(false);
        nearButton.setClickable(false);
        highlightedButton.setClickable(false);
        top20Button.setClickable(false);

        Intent i = new Intent();
        i.putExtra("showDialog", false);
        i.addFlags(Intent.FLAG_ACTIVITY_SINGLE_TOP);
        i.setClass(Search.this, Top20.class);
        startActivity(i);
        finish();

    }
});

所有更正之后，其仍然相同:S当我像疯子一样单击时，历史记录堆栈上有多个活动，因此我必须退出多次.

After all this correction its still the same :SWhen i click like a mad person multiple activites are on the history stack and i must quit multiple times.

有什么建议吗?我在做什么错了?

Any suggestions ? What m i doing wrong?

推荐答案

您可以使用以下代码: btn.setEnabled(false);

You can use following code: btn.setEnabled(false);

btn.setOnclickListener(new View.onClickListener(){

      public void onClick(View v) {
            btn.setEnabled(false);

      }
});

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